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igor_vitrenko [27]
3 years ago
8

What is the greatest common factor of 30b^2, 80b^2, and 20b^2

Mathematics
1 answer:
victus00 [196]3 years ago
3 0

Answer:

10b²

Step-by-step explanation:

First, let's look at the coefficients. The greatest common factor of all three numbers 30, 80, and 20, is 10. Now, let's look at the variables. All three terms are divisible by b² (with no remainder). We can combine 10 and b² so they become one term, and that is the GCF. 10b².

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Theorem: The segment joining the midpoints of two sides of a triangle is parallel to the third side and half its length. A two-c
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Answer:  By the slope formula.

Step-by-step explanation:

Given: ABC is a triangle (shown below),

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Coordinate of E are  (\frac{2+8}{2} , \frac{2+4}{2} ) = (\frac{10}{2} , \frac{6}{2} )= (5,3)

By the distance formula,

DE=\sqrt{(5-4)^2+(3-5)^2}=\sqrt{5}

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By the slope formula,

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Slope of DE =  \frac{3-5}{5-4} = \frac{-2}{1} = -2


            Statement                                              Reason

1. The coordinate of D are (4,5)  and           1. By the midpoint formula

the coordinate of  E are (5,3)

2. The length of DE = √5                            2. By the Distance formula

The length AC = 2√5 ⇒ Segment DE

is half the length of segment AC

3. The slope of DE = -2 and the                3. By the slope formula

slope of AC = -2

4. DE║AC                                                   4. Slopes of parallel lines are equal


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