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shtirl [24]
2 years ago
12

Find the area of the trapezoid by decomposing it into other shapes. A) 56 cm2 B) 60 cm2 C) 64 cm2 D) 72 cm2 Eli

Mathematics
1 answer:
Marrrta [24]2 years ago
4 0

Answer:

Option C. 64\ cm^2

Step-by-step explanation:

see the attached figure N 1 to better understand the problem

we know that

The trapezoid can be decomposed into two right triangles and a rectangle

see the attached figure N 2

so

The area of the trapezoid is equal to the area of two right triangles and one rectangle

The area of trapezoid is equal to

A=\frac{1}{2}(5)(4)+(12)(4)+\frac{1}{2}(3)(4)

A=10+48+6

A=64\ cm^2

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3 years ago
Find the -scores that bound the middle 96 of the area under the standard normal curve by using the TI-84 calculator.
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Answer:

\alpha=1-0.96 =0.04

And \alpha/2= 0.02 and if we use the following function on the Ti84 plus we got:

invNorm(0.02,0,1)

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And the values with the middle 96% of the values are:

z_{\alpha/2}= \pm 2.054

Step-by-step explanation:

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\alpha=1-0.96 =0.04

And \alpha/2= 0.02 and if we use the following function on the Ti84 plus we got:

invNorm(0.02,0,1)

invNorm(1-0.02,0,1)

And the values with the middle 96% of the values are:

z_{\alpha/2}= \pm 2.054

6 0
3 years ago
A triangle with two congruent sides is always a 45-45-90 triangle
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5 0
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A sneaker company can make 50 pairs of sneakers for every 6 yards of material. Make a table to show the relation between materia
Law Incorporation [45]

A sneaker company can make 50 pairs of sneakers for every 6 yards of material.

Then in each case you can consider proportion.

1. 50 pairs -- 6 yards,

80 pairs -- x yards.

Mathematically,

\dfrac{50}{80}=\dfrac{6}{x},\\ \\x=\dfrac{80\cdot 6}{50}=9.6\ yards.

2. 50 pairs -- 6 yards,

100 pairs -- x yards.

Mathematically,

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3. 50 pairs -- 6 yards,

120 pairs -- x yards.

Mathematically,

\dfrac{50}{120}=\dfrac{6}{x},\\ \\x=\dfrac{120\cdot 6}{50}=14.4\ yards.

4. 50 pairs -- 6 yards,

140 pairs -- x yards.

Mathematically,

\dfrac{50}{140}=\dfrac{6}{x},\\ \\x=\dfrac{140\cdot 6}{50}=16.8\ yards.

Thus, the table is

\begin{array}{cc}\text{Pairs}&\text{Yards}\\50&6\\80&9.6\\100&12\\120&14.4\\140&16.8\end{array}

The domain of the relation is the set \{50,80,100,120,140\} and the range of the relation is \{6,9.6,12,14.4,16.8\}.See attached diagram for the graph of the relation.

4 0
3 years ago
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