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shtirl [24]
3 years ago
12

Find the area of the trapezoid by decomposing it into other shapes. A) 56 cm2 B) 60 cm2 C) 64 cm2 D) 72 cm2 Eli

Mathematics
1 answer:
Marrrta [24]3 years ago
4 0

Answer:

Option C. 64\ cm^2

Step-by-step explanation:

see the attached figure N 1 to better understand the problem

we know that

The trapezoid can be decomposed into two right triangles and a rectangle

see the attached figure N 2

so

The area of the trapezoid is equal to the area of two right triangles and one rectangle

The area of trapezoid is equal to

A=\frac{1}{2}(5)(4)+(12)(4)+\frac{1}{2}(3)(4)

A=10+48+6

A=64\ cm^2

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The perimeter of the triangle shown is 412 meters. Find the length of each side.
Fudgin [204]

Answer:

x meters= 35

5x meters= 175

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Step-by-step explanation:

x + 5x + (6x - 8)= 412

12x - 8= 412

12x = 412 + 8

12x = 420

x= 35

5x = 35× 5

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6x - 8= 6(35) - 8

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7 0
2 years ago
Pleaseeee help!!!! I will mark you as brainlinest for correct answer!!!!!!!!
Anni [7]
I used a graphing calculator for this.

The solution my calculator got was:

(-2.625, 0.688) My calculator is very accurate, I don't think the test expects it to be like that.

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~kaikers
5 0
3 years ago
Solve for x. Show your work. For each picture, please
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If two secants intersect from a point outside of the circle, then the product of the lengths of the secant and its external segment equals the product of the other secant and its external segment.

#1
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x = 7

#2
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3 years ago
Approximate: log5 4/7
Evgesh-ka [11]
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therefore

log5 (4/7)= log5 (4)- log5 (7)

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 Use the calculator: 

<span> <span>log 5 4 =0.8613531161 </span></span>

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<span>log 5 7 =1.2090619551</span>

<span>log5 (4/7)= log5 (4)- log5 (7)=-0.347708839</span>

6 0
3 years ago
Read 2 more answers
The expression sin 50 cos 40 + cos 50 sin 40 is equivalent to
enyata [817]
Sin (a+b) = sin a. cos b + cos a. sin b

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sin 50° . cos 40° + cos 50° . sin 40° = 1
8 0
3 years ago
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