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creativ13 [48]
3 years ago
8

Which expression gives the distance between the points (-3,4 and (6,-2)

Mathematics
1 answer:
krok68 [10]3 years ago
8 0

Answer:

10.8

Step-by-step explanation:

We can find the distance using the distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

We then substitute (-3,4) as (x_1,y_1) and (6,-2) as (x_2,y_2).

d=\sqrt{(6--3)^2+(-2-4)^2} \\d=\sqrt{(9)^2+(-6)^2} \\d=\sqrt{81+36}\\d=\sqrt{117}=10.8

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How many and what type of solutions does the equation have?
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Let's solve the equation 2k^2 = 9 + 3k
First, subtract each side by (9+3k) to get 0 on the right side of the equation
2k^2 = 9 + 3k
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As you see, we got a quadratic equation of general form ax^2 + bx + c, in which a = 2, b= -3, and c = -9.
Δ = b^2 - 4ac
Δ = (-3)^2 - 4 (2)(-9)
Δ<u /> = 9 + 72
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Δ<u />>0 so the equation got 2 real solutions:
k = (-b + √Δ)/2a = (-(-3) + √<u />81) / 2*2 = (3+9)/4 = 12/4 = 3
AND
k = (-b -√Δ)/2a = (-(-3) - √<u />81)/2*2 = (3-9)/4 = -6/4 = -3/2

So the solutions to 2k^2 = 9+3k are k=3 and k=-3/2

A rational number is either an integer number, or a decimal number that got a definitive number of digits after the decimal point.

3 is an integer number, so it's rational.
-3/2 = -1.5, and -1.5 got a definitive number of digit after the decimal point, so it's rational.

So 2k^2 = 9 + 3k have two rational solutions (Option B).

Hope this Helps! :)
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