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aev [14]
3 years ago
5

3.) Graph f(x)=3^x.​

Mathematics
1 answer:
ollegr [7]3 years ago
7 0

Answer:

f(x)=3^x plot = see attachment

Step-by-step explanation:

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I will give brainliest if you help me
ZanzabumX [31]

Answer:

it would still be the same length due to the fact that it did not change lengths.

Step-by-step explanation:

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3 years ago
Point A, located at (-2, 4), is translated down 6 units. What are the coordinates of A'?
lara [203]
(-8, 4)                             hope that helps

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3 years ago
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If f(x) = 3^2 + 10x and g(x) = 2x-4, find (f-g)(x).
Marat540 [252]

What we know:      

f(x)=3^2+10x\\g(x)=2x-4                

(Also, 3^2=9)

What we need to solve:

(f-g)(x)             (This is equal to f(x)-g(x))

How you have to subtract f(x) with g(x) to get:

(f-g)(x) = f(x)-g(x) = 9+10x+2x-4 = 12x+5

Thus, the answer would be:

12x+5

3 0
3 years ago
A Water flows through a pipe at a rate of 10 milliliters every 8.5 seconds. Express this
Alexandra [31]

Answer:

The answer to the nearest hundredth is 0.07 liters per minute

Step-by-step explanation:

In this question, we are told to express the given metric in liters per minute.

The key to answering this question, is to

have the given measurements in the metric in which we want to have the answer.

Hence, we do this by converting milliliters to liters and seconds to minute.

Let’s start with milliliters;

Mathematically;

1000 milliliters = 1 liters

10 milliliters = x liters

x * 1000 = 10 * 1

x = 10/1000

x = 1/100

x = 0.01 liters

For the seconds;

We need to convert the seconds to minutes;

Mathematically;

60 seconds = 1 minute

8.5 seconds = y minutes

60 * y = 8.5 * 1

y = 8.5/60

y = 0.14167 minutes

Now, our rate of flow is liters per minute, that means we have to divide the volume by the time;

Hence, we have ;

0.01/0.14167 = 0.070588235294

Which to the nearest hundredth is 0.07

6 0
4 years ago
Enter the solution to the inequality in the box.<br><br><br><br> 8+4(x−3)+3x≤24
xxMikexx [17]
8+4x-12+3x<=24
-4+7x<=24
7x<=28
X<=4
5 0
3 years ago
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