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aev [14]
3 years ago
5

3.) Graph f(x)=3^x.​

Mathematics
1 answer:
ollegr [7]3 years ago
7 0

Answer:

f(x)=3^x plot = see attachment

Step-by-step explanation:

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4/12 of a cake was left over if another 3/12 of the cake is eaten
inn [45]
There would be 1/12 of the cake left. 
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HELP ME SOMEONE!!!!!!!!!!1
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The answer is D. you can choose your words carefully
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(x^2 - x^(1/2))/(1-x^(1/2))
Levart [38]
\frac { \left( { x }^{ 2 }-{ x }^{ \frac { 1 }{ 2 }  } \right)  }{ \left( 1-{ x }^{ \frac { 1 }{ 2 }  } \right)  }

\\ \\ =\frac { \left( { x }^{ 2 }-\sqrt { x }  \right)  }{ \left( 1-\sqrt { x }  \right)  } \cdot 1

\\ \\ =\frac { \left( { x }^{ 2 }-\sqrt { x }  \right)  }{ \left( 1-\sqrt { x }  \right)  } \cdot \frac { \left( 1+\sqrt { x }  \right)  }{ \left( 1+\sqrt { x }  \right)  }

\\ \\ =\frac { { x }^{ 2 }+{ x }^{ 2 }\sqrt { x } -\sqrt { x } -x }{ 1+\sqrt { x } -\sqrt { x } -x }

\\ \\ =\frac { -\sqrt { x } \left( 1-{ x }^{ 2 } \right) -x\left( 1-x \right)  }{ \left( 1-x \right)  }

\\ \\ =\frac { -\sqrt { x } \left( 1+x \right) \left( 1-x \right) -x\left( 1-x \right)  }{ \left( 1-x \right)  }

\\ \\ =\frac { \left( 1-x \right) \left\{ -\sqrt { x } \left( 1+x \right) -x \right\}  }{ \left( 1-x \right)  }

\\ \\ =-\sqrt { x } \left( 1+x \right) -x\\ \\ =-{ x }^{ \frac { 1 }{ 2 }  }\left( 1+{ x }^{ \frac { 2 }{ 2 }  } \right) -x

\\ \\ =-{ x }^{ \frac { 1 }{ 2 }  }-{ x }^{ \frac { 3 }{ 2 }  }-x\\ \\ =-\sqrt { x } -\sqrt { { x }^{ 3 } } -x
3 0
3 years ago
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The picture shows a triangular island:
sergiy2304 [10]

Answer:

The expressions that show the value of q are

1) q=\sqrt{r^{2}+s^{2}}

2) q=\frac{s}{cos(55\°)}

3) q=\frac{r}{sin(55\°)}

4) q=\frac{s}{sin(35\°)}

5) q=\frac{r}{cos(35\°)}

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

case A)

In the right triangle of the figure

Applying the Pythagoras Theorem

q^{2}=r^{2}+s^{2}

q=\sqrt{r^{2}+s^{2}}

case B)

In the right triangle of the figure

cos(55\°)=\frac{s}{q}

solve for q

q=\frac{s}{cos(55\°)}

case C)

In the right triangle of the figure

sin(55\°)=\frac{r}{q}

solve for q

q=\frac{r}{sin(55\°)}

case D)

In a right triangle

if A+B=90\°

then

cos(A)=sin(B)

therefore

q=\frac{s}{cos(55\°)}------> q=\frac{s}{sin(35\°)}

q=\frac{r}{sin(55\°)} ------>  q=\frac{r}{cos(35\°)}

4 0
3 years ago
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Callaway is thinking about entering the golf ball market. The company will make a profit if its market share is more than 20%. A
Vedmedyk [2.9K]

Answer:

z=\frac{0.224 -0.2}{\sqrt{\frac{0.2(1-0.2)}{624}}}=1.499  

p_v =P(Z>1.499)=0.0669  

If we compare the p value obtained and the significance level assumed \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion is not significantly higher than 0.2 or 20%.  

Step-by-step explanation:

How would you make the decision if you were Callaway management? Would you use hypothesis testing?

The best way to test the claim if with a proportion test. The procedure is explained below.

1) Data given and notation

n=624 represent the random sample taken

X=140 represent the golf ball purchasers will buy a Callaway golf ball

\hat p=\frac{140}{624}=0.224 estimated proportion of golf ball purchasers will buy a Callaway golf ball

p_o=0.2 is the value that we want to test

\alpha represent the significance level

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion is more than 0,2 or 20%:  

Null hypothesis:p\leq 0.2  

Alternative hypothesis:p > 0.2  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.224 -0.2}{\sqrt{\frac{0.2(1-0.2)}{624}}}=1.499  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level is not provided but let's assume \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(Z>1.499)=0.0669  

If we compare the p value obtained and the significance level assumed \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion is not significantly higher than 0.2 or 20%.  

8 0
3 years ago
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