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3 years ago

Show your work and check answer. -3x=5x+8

2 answers:

7 0

Let's solve your equation step-by-step.−3x=5x+8Step 1: Subtract 5x from both sides.−3x−5x=5x+8−5x−8x=8Step 2: Divide both sides by -8.−8x−8=8−8x=−1 Answer =-1 I used a calculator

mylen [45]3 years ago

6 0

Here is the work from step to step. hope you can understand it.
-3x=5x+8
=-5x -5x
=2x=8
=2x/2=8/2
=x=4
answer- 4

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0.24 + 4.25 equals what ?

love history [14]

Answer:

4.49

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Jillian sold 12% of the candy bars the class sold to raise money for a new water cooler in the school. If she sold 36 candy bars

Len [333]

Answer:

So we can write an equation to solve this:

12/100 = 36/x

And then we are going to solve for x

x(12/100) = 36

36 x (100/12) = 300

The total number of candy bars was 300

6 0

3 years ago

Need pre-cal help. Will mark best answer brainliest

OlgaM077 [116]

so, let's keep in mind that

$\bf \begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}$

so let's make a quick table of those solutions, say A, B, C solutions with x,y,z liters of acid, with an acidity of 0.25, 0.40 and 0.60 respectively.

$\bf \begin{array}{lcccl} &\stackrel{solution}{quantity}&\stackrel{\textit{\% of }}{amount}&\stackrel{\textit{liters of }}{amount}\\ \cline{2-4}&\\ A&x&0.25&0.25x\\ B&y&0.40&0.4y\\ C&z&0.60&0.6z\\ \cline{2-4}&\\ mixture&78&0.45&35.1 \end{array} \\\\\\ \begin{cases} x+y+z=78\\ 0.25x+0.4y+0.6z=35.1 \end{cases}$

we know she's using "z" liters and those are 3 times as much as "y" liters, so z = 3y.

$\bf \begin{cases} x+y+3y=78\\ x+4y=78\\[-0.5em] \hrulefill\\ 0.25x+0.4y+0.6(3y)=35.1\\ 0.25x+0.4y=1.8y=35.1\\ 0.25x+2.2y=35.1 \end{cases}\implies \begin{cases} x+4y=78\\\\ 0.25x+2.2y=35.1 \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ x+4y=78\implies \boxed{x}=78-4y \\\\\\ \stackrel{\textit{using substitution on the 2nd equation}}{0.25\left( \boxed{78-4y} \right)+2.2y=35.1}\implies 19.5-y+2.2y=35.1$

$\bf 1.2y=15.6\implies y=\cfrac{15.6}{1.2}\implies \blacktriangleright y=13 \blacktriangleleft \\\\\\ x=78-4y\implies x=78-4(13)\implies \blacktriangleright x=26 \blacktriangleleft \\\\\\ z=3y\implies z=3(13)\implies \blacktriangleright z=39 \blacktriangleleft \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \stackrel{25\%}{26}\qquad \stackrel{40\%}{13}\qquad \stackrel{60\%}{39}~\hfill$

5 0

2 years ago

a student found the slope of a line that passes through the points (1,14) and (3,4) to be 5. what mistake did she make?

mariarad [96]

$x_{1}=1$
$x_{2}= 3$
$y_{1} =14$
$y_{2}=4$
$Slope= \frac{rise}{run} = \frac{ y_{2} - y_{1} }{ x_{2} - x_{1} } = \frac{4-14}{3-1} = \frac{-10}{2} =-5$

answer: The student flipped the y values

3 0

3 years ago

Someone please, HELP!!!!

Brrunno [24]

Range: maximum - minimum
IQR: third quartile - first quartile
median: middle number once all numbers are put in numerical order

8 0

3 years ago