The horizontal component of the equation of motion is given by:
. . . (1)
where: v is the velocity of projection, t is the time and theta is the angle of projection
The vertical component of the equation of motion is given by:
. . . (2)
where, y_0 is the height above the ground of projection.
Given that a<span> shot put is thrown upward with a velocity of 35 ft./sec. at a height of 4 ft. and an angle of 40°.
This meanns that v = 35 ft/sec; y_0 = 4 ft; and theta = </span>40°.
Let the height of the shot put above the ground at the time the shot put's horizontal distance from the point of projection is 40 ft be h, then we have:
Solving the quadratic equation, we have:
But t must not be negative, thus we disregard the negative and thus have:
Substituting for t into equation (1) gives:
Substituting for h into t, we have:
Therefore, the time it will <span>take for the shot put to be a horizontal distance of 40 ft. from the person throwing it is 43.5 seconds.</span>
Answer:
third answer is correct
Step-by-step explanation:
hello,
we need to compute
5*(-1)+(-2)*(-1)=-5+2=-3
-6*(-1)+(2)*(-1)=6-2=4
so the correct answer is
-3
4
hope this helps
The coefficient of (3y² + 9)5 is <u>15</u>.
A polynomial is of the form a₀xⁿ + a₁xⁿ⁻¹ + a₂xⁿ⁻² + ... + aₙ₋₁x + aₙ.
Here, x is the variable, aₙ is the constant term, and a₀, a₁, a₂, ..., and aₙ₋₁, are the coefficients.
a₀ is the leading coefficient.
In the question, we are asked to identify the coefficient of (3y² + 9)5.
First, we expand the given expression:
(3y² + 9)5
= 15y² + 45.
Comparing this to the standard form of a polynomial, a₀xⁿ + a₁xⁿ⁻¹ + a₂xⁿ⁻² + ... + aₙ₋₁x + aₙ, we can say that y is the variable, 15 is the coefficient, and 45 is the constant term.
Thus, the coefficient of (3y² + 9)5 is <u>15</u>.
Learn more about the coefficients of a polynomial at
brainly.com/question/9071229
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Answer:
150656
Step-by-step explanation:
i used a calculator and google