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Lesechka [4]
3 years ago
13

List the elements of the set, then indicate the cardinality of the set. HINT [See Example 2.] (Enter your answers as a comma-sep

arated list. Enter your answers from smallest to largest.) A = {k | k is a positive integer and 8 < k < 16}.
Mathematics
1 answer:
Gnom [1K]3 years ago
7 0

Answer:

Elements of the set: 9,10,11,12,13,14,15

Cardinality of the set: 7

Step-by-step explanation:

Firstly the set describes that A contains the values of k which are positive integers only.

Secondly it limits the values of k to be between 8 and 16, exclusive of both upper and lower limits.

Therefore we list all positive integers between 8 and 16 i.e. 9,10,11,12,13,14,15

Finally, we count the numbers of elements in the set which is also known as cardinality of the set i.e. 7 for our given set.

You might be interested in
Which equations show you how to find 16-9?
Pie
The correct answer is B.
16-9=7
So, 7+9=16.

If we add to 9 only 1 (out of those 7) we have then 10, remaining 6.
9+1=10

Now, if to 10 we add the remaining 6 we will have the final 16.
10+6=16

16-9=7 <=> 9+7=16 <=> (9+1)+6=16
5 0
3 years ago
I need to know what to do for this problem. I am confused. Thanks♡
steposvetlana [31]
$1,154 will be what each kid needs to raise, you must add up both travel expenses, which totals $10,386, and divide that with the number of children (9), and you get your answer:)! hope this helps.
6 0
3 years ago
Read 2 more answers
In two or three sentences explain how you would solve for the real solutions of the following equation: please help asap!!
g100num [7]

the real solutions for the equation x^{3}=-64 are -

x=4,2+-2\sqrt{3i}

Step-by-step explanation:

   x^{3} = - 64

   x^{3} +64  = 0

   We can write 64 as  4^{3}

  x^{3} + 4^{3} = 0

  using the identity  ( x^{3}+y^{3} = (x+y)(x^{2} -xy+y^{2} ) )

we get,

  = (x+4) (x^{2} -x*4+4^{2} )

  = (x+4)(x^{2} -4x+16)    ....................(1)

 solving the quadratic equation  ,

   x^{2} -4x+16 =0

solutions of this quadratic equation can be obtained by

   x=-b +- \sqrt{b^{2}-4ac } /2a

let use y for factors

x=-(-4x)+-\sqrt{(-4x^{2} )-4*x^{2} *16}  / 2*x^{2}

x=4x+-\sqrt{16x^{2} -64x^{2} } /2x^{2}

x=4+-\sqrt{16-64}/2

x=4+-4\sqrt{3i} /2

<u />x=2+-2\sqrt{3i}    ..................(2)

from the equation 1 we have,

x-4=0

which gives solution x=4

and from equation 2 we got  x=2+-2\sqrt{3i}

so the real solutions for the equation x^{3}=-64 are -

x=4,2+-2\sqrt{3i}

3 0
2 years ago
How do you get the answer to 10+12y=2y+40
stepladder [879]
Y = 3

Exp:

10 + 12y = 2y + 40
- 2y = - 2y

10 + 10y = 40
-10 -10

10y = 30
/ 10 / 10

y = 3
4 0
2 years ago
What is the slope of the line through (-5, -3) and (-5, -7)?
Paul [167]

Answer:

The answer is undefined.

Step-by-step explanation:

Slope is found using this equation: y-y1/x-x1. Fill in the coordinates to this equation. It should now look like this. -7--3/-5--5. When subtracting from two negatives, it changes into a positive. For example, -7--3 becomes -7+3, which equals -4. The same thing applies for the second part. -5--5 becomes -5+5, which equals 0. So, your slope is -4/0. However, when a 0 is in the denominator, it becomes undefined. So, the answer is undefined.

5 0
3 years ago
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