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3 years ago

I don’t understand because I’m not good with money

Mathematics

1 answer:

lakkis [162]3 years ago

4 0

So you divide 12.00 by 0.75 and you get 16 which is the number of cookies he sold.

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Solve x2 – 18x + 81 = 4 by completing the square. Select any solutions that apply.

Masteriza [31]

Answer:

7 and 11

Step-by-step explanation:

3 0

2 years ago

Which of the following equations is equivalent to 2/3 x - 1/2 y = 6? 2x - y = 6 2x - y = 36 4x - 3y = 36

boyakko [2]

Answer: THE LAST OPTION

Step-by-step explanation:

1. You have the following equation given in the problem:

$\frac{2}{3}x-\frac{1}{2}y=6$

2. If you multiply both sides of the equation shown above by 6, you obtain the following:

$\frac{2*6}{3}x-\frac{1*6}{2}y=6*6$

$\frac{12}{3}x-\frac{6}{2}y=36$

3. When you simplify the equation, you obtain the following equivalent equation:

$4x-3y=36$

5 0

3 years ago

Is the following shape a rectangle

Gelneren [198K]

Answer:

Step-by-step explanation:

no because the adjacent sides are not perpendicular.

4 0

3 years ago

A circle has a radius of three. An arc in the circle has essential angle of 20°. What is the length of the arc

Nataliya [291]

Answer:

1.048

Step-by-step explanation:

$(thiter \div 360) \times \pi \times diameter$

$(20 \div 360) \times \pi \times 6$
After calculating the answer is 1.048

6 0

3 years ago

Help with 5b please . thank you.

Allushta [10]

Answer:

See explanation

Step-by-step explanation:

We are given f(x)=ln(1+x)-x+(1/2)x^2.

We are first ask to differentiate this.

We will need chain rule for first term and power rule for all three terms.

f'(x)=(1+x)'/(1+x)-(1)+(1/2)×2x

f'(x)=(0+1)/(1+x)-(1)+x

f'(x)=1/(1+x)-(1)+x

We are then ask to prove if x is positive then f is positive.

I'm thinking they want us to use the derivative part in our answer.

Let's look at the critical numbers.

f' is undefined at x=-1 and it also makes f undefined.

Let's see if we can find when expression is 0.

1/(1+x)-(1)+x=0

Find common denominator:

1/(1+x)-(1+x)/(1+x)+x(1+x)/(1+x)=0

(1-1-x+x+x^2)/(1+x)=0

A fraction can only be zero when it's numerator is.

Simplify numerator equal 0:

x^2=0

This happens at x=0.

This means the expression,f, is increasing or decreasing after x=0. Let's found out what's happening there. f'(1)=1/(1+1)-(1)+1=1/2 which means after x=0, f is increasing since f'>0 after x=0.

So we should see increasing values of f when we up the value for x after 0.

Plugging in 0 gives: f(0)=ln(1+0)-0+(1/2)0^2=0.

So any value f, after this x=0, should be higher than 0 since f(0)=0 and f' told us f in increasing after x equals 0.

8 0

2 years ago