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Mkey [24]
3 years ago
14

How do the lateral and total surface area of a cylinder differ ?

Mathematics
1 answer:
vichka [17]3 years ago
8 0
The lateral surface area of a cylinder is just the long side connecting the bases, whereas the total surface area includes both the lateral surface area and area of the two circular bases.

SA_l_a_t=2 \pi rh (Imagine a rectangle with the circumfrence of the base as one side and the height as the other being folded around)

SA = 2 \pi rh + 2 \pi r^2 (Plus the area of two circles)

The literal difference between surface areas would be the two bases 2πr² if you need that.
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A bag contains 5 blue marbles, 2 black marbles, and 3 red marbles. A marble is randomly drawn from the bag.
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Since you are not allowed to draw a black marble, then you have only 7 ways to draw either a blue or a red marble. The sum of all marbles is 10. So the probability of not drawing a black marble is 7/10 and the probability of drawing a red marble is 2/10 or 1/5.
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What is the surface area of the rectangle pyramid below?​
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What percent of all children like the Simpsons? Round your answer to the nearest tenth of a percent. Type a numerical answer
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To make it simpler, make it,out of 100 by dividing it all by 3. This will make it:

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PLS HELP ASAP I WILL IVE BRAINLIST ANSWER!!!!!Leon verified that the side lengths 21, 28, 35 form a Pythagorean triple using thi
Juliette [100K]

Answer:

Leon is correct. (Option 1)

Step-by-step explanation:

Given that Leon verified that the side lengths 21, 28, 35 form a Pythagorean triple using this procedure.

Step 1: Find the greatest common factor of the given lengths: 7

Step 2: Divide the given lengths by the greatest common factor: 3, 4, 5

Step 3: Verify that the lengths found in step 2 form a Pythagorean triple.

we have to explain whether or not Leon is correct.

As, 3,4,5 forms a Pythagorean triplet i.e satisfies the Pythagoras theorem

Hypotenuse^2=Base^2+Perpendicular^2

⇒ 5^2=3^2+4^2

Let a, b, c forms a Pythagorean triplet

a^2+b^2=c^2

Multiplied by 4 on both sides

⇒ 4a^2+4b^2=4c^2

⇒ {2a}^2+{2b}^2={2c}^2

Hence, we say 4a, 4b and 4c also forms a Pythagorean triplet.

∴ multiplying every length of a Pythagorean triple by the same whole number results in a Pythagorean triple.

Hence, Leon is correct.

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