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Flauer [41]
3 years ago
11

If trapezoid JKLM is translated according to the rule (x,y)—> (x+2, y - 6), what are the coordinates of point L

Mathematics
1 answer:
guapka [62]3 years ago
3 0

Answer:

<em> ( x, y) is translation '2' units right and '6' units down </em>

<em> (x ,y))—> (x +2 ,y-6)</em>

Step-by-step explanation:

<u><em>Explanation</em></u>:-

Type of transformation                            change to co-ordinate point

vertical translation up 'd' units                (x,y)  changes to  (x  , y+d)

<em>vertical translation down 'd' units          (x,y)  changes to  (x  , y-d)</em>

Horizontal translation left 'c' units          (x,y)  changes to  (x-c  , y)

Horizontal translation right 'c' units            (x,y)  changes to  (x+c  , y)

Now by use above table

given data  ( x, y) is translation '2' units right and '6' units down

(x ,y))—> (x +2 ,y-6)

<u><em>Final answer:-</em></u>

<em> ( x, y) is translation '2' units right and '6' units down </em>

<em> (x ,y))—> (x +2 ,y-6)</em>

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Match each pair of points to the equation of the line that is parallel to the line passing through the points.
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Answer:

B(5,2) \:\: C(7,-5) \:\: \rightarrow y=-3.5x-15

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We need to match the slope of the function with the slope of the lines connecting the two points given. The slope of the lines are as follows:

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H(4,4)\:\: I(8,9)=\frac{4-9}{4-8} =1.25

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F(-7,12)\:\: G(3,-8)=\frac{12--8}{-7-3}=-2

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Now,

the slope of the line BC matches with the slope of  y=-3.5x-15.

the slope of the line DE matches with the slope of y=-0.5x-3.

the slope of the line HI matches with the slope of y=1.25x+4.

the slope of the line LM matches with the slope of  y=5x+9.

and the slopes of the lines FG and JK do not match with any of the functions given.

Thus,

B(5,2) \:\: C(7,-5) \:\: \rightarrow y=-3.5x-15

D(11,6)\:\: E(5,9)\:\: \rightarrow y=-0.5x-3

H(4,4)\:\: I(8,9) \:\: \rightarrow y=1.25x+4

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