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nignag [31]
3 years ago
10

Una mujer de 5 pies de altura esta de pie cerca de un farol que tiene 12 pies de altura, . Encuentre una función que modele la l

ongitud de su sombra en términos de distancia desde la base del farol. un triangulo isósceles tiene un perímetro de 8cm. Encuentre una función que moldee su área a en términos de la longitud de su base
Mathematics
1 answer:
professor190 [17]3 years ago
6 0

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Arlene us showing her work in simplifying(−7.9)+8.2−3.4+2.1 identify any error in her work or in her reasoning.
Brums [2.3K]
Keep doing each step manually, and see where it slips up: −7.9+8.2−3.4+2.1=−1 −7.9+8.2+(−3.4)+2.1=−1 −7.9+(−3.4)+8.2+2.1=−1 (−7.9+(−3.4))+(8.2+2.1)=−1 −11.3+10.3=−1

4 0
4 years ago
Saved
nadezda [96]
The answer is 3 because the mean of the numbers on both of them are 3
Hope it helped:)

4 0
3 years ago
a rocket is 1 mile above thw earth in 30 seconds and 5 miles above the earth in 2.5 minutes what is the rockets rate of change i
Veronika [31]
Rate of Change:

At 1 mile in 30 seconds.
At  5 miles in 2.5 minutes.  2.5 minutes = 2.5*60 = 150 seconds.

Rate of change =   Change in height / Change in time

                            =   (h₂-h₁)/(t₂-t₁)

                            =   (5 -1) /(150 -30) = 4/120 = (1/30) = 0.0333 miles per second.

                             = (1/30) miles per second or 0.0333 miles per second.


To have the answer in miles per minute.

         (1/30) miles per second = (1/30) miles/second.

60 seconds = 1minute
1 second = (1/60) minute.

(1/30) miles/second  =  (1/30) miles/(1/60)minute
                                   =   (1/30) *60 miles / minute
                                   =    2 miles per minute.
8 0
3 years ago
The universal set in this diagram is the set of integers from 1 to 15. place the integers in the correct place in the venn diagr
neonofarm [45]

Answer:


Step-by-step explanation:

Given :  universal set in this diagram is the set of integers from 1 to 15.

Solution :

The intersection of odd integer,multiples of 3 and Factors of 15 are 3,15

The intersection of odd integer and Factors of 15 are 1,5

The intersection of odd integer,multiples of 3 is 9

The remaining multiples of 3 are 6,12

The remaining odd integers are 7,11,13

Now the remaining integers are 2,4,8,10,14 and these integers must be placed in the boxes outside the circles Since they does not belong any intersection or odd integer or factor of 15 .

Refer the attached figure for the answer.

3 0
3 years ago
Read 2 more answers
Find an equation of the line that satisfies the given conditions. through (9, 7); perpendicular to the line y = 5
cluponka [151]
The answer would defintley be 69 if you want the right answer.
5 0
3 years ago
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