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Andre45 [30]
3 years ago
10

Please help me with this ASAP (Geometry)

Mathematics
1 answer:
9966 [12]3 years ago
7 0
4) They are congruent by ASA.

5) you can set up a proportion.

original height / shadow = original of tree/ shadow of tree

18/21 = x/14
21x = 252
x = 12

SO the height of the tree is 12

Hope this helps :)
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Labyrinth Middle School is 363 feet long. Tabitha makes a scale model of the school and the drawing is 33 inches long. What is t
defon

Answer:

The Answer is 1 inch represents 11 feet.

Step-by-step explanation:

The original measurement, or the measurement of the middle school, is 363 feet. The measurement of the drawing is 33. To get the answer, you take 363 and divide it by 33 to get the scale factor of 11. This means that for each inch, there is 11 feet. Hope this helps!

5 0
3 years ago
Consider the following expression: (1 + x)^n. A) Use the Binomial Theorem to find the first four terms of this polynomial. B) Wh
sergiy2304 [10]
Given:

The expression:  (1 + x)^n

The Binomial Theorem is used to predict the products of a binomial raised to a certain power, n, without multiplying the terms one by one. 

The following formula is used:

(a + b)^n = nCk * a^(n-k) * b^k

we have (1 +x)^n,

where a = 1 
            b = x
let n = 4

First term, k = 1

4C1 = 4

first term: 4*(1^(4-1))*x^1

Therefore, the first term is 4x. Do the same for the next three terms. 

2nd term: k =2 
3rd term: k = 3
4th term: k = 4
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3 0
3 years ago
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adell [148]
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3 0
3 years ago
Please explain I don’t know how to factor odd numbers
goldenfox [79]
This should be the answer

3 0
3 years ago
Solve with cramer's rule x+2y+3z=11, 2x+y+2z=10, 3x+2y+z=9
nalin [4]

Answer:

x = 2 , y = 0 , z = 3

Step-by-step explanation:

Cramer's rule is a rule through which we can find the solution of linear equation.

we have the three linear equations as

x+2y+3z=11

2x+y+2z=10

3x+2y+z=9

AX=B  

A: coefficient matrix

X= unknown vectors(x,y,z)

D = values of the linear equation (11 , 10 , 9)

now we find the determinant of the given linear equation

determinant of the matrix will be

A = \left[\begin{array}{ccc}1&2&3\\2&1&2\\3&2&1\end{array}\right]  = 1(1-4) - 2(2-6) + 3(4 - 3)

                    = 1(-3) - 2(-4) + 3(1)

                    = -3+8+3 = 8

also D\neq 0

so the determinant is Non zero we can apply Cramer's rule

we will be replacing the first column of the coefficient matrix A with the values of D

by replacing the first column we will get the value of the variable 'x'

Dx =  \left[\begin{array}{ccc}11&2&3\\10&1&2\\9&2&1\end{array}\right]   = 11(1-4) -2(10-18) + 3(20-9) = -33+16+33 = 16

x = \frac{Dx}{D}  = \frac{16}{8} = 2

similarly

Dy = \left[\begin{array}{ccc}1&11&3\\2&10&2\\3&9&1\end{array}\right] = 1(10-18) -11(2-6) + 3(18 -30) = -8 +44 -36 = 0

y = \frac{Dy}{D} = 0

Dz= \left[\begin{array}{ccc}1&2&11\\2&1&10\\3&2&9\end{array}\right] = 1(9 - 20) -2(18 - 30) + 11(4 -3) = -11 +24 +11 = 24

z = \frac{Dz}{D} = \frac{24}{8} = 3

so we have the solution as

x = 2 , y = 0 , z = 3

Therefore the solution for the given linear equations is (2,0,3).

3 0
3 years ago
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