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KonstantinChe [14]
3 years ago
9

Alemu, Tulu, Kassa and Tegitu worked for 4 hours, 6 hours, 5 hours

Mathematics
1 answer:
GaryK [48]3 years ago
6 0
As a group they were paid $1000 after putting in 4+6+5+5 = 20 worker-hours.
$1000/(20 worker-hours) = $50/(worker-hour)
Alemu received 4*$50 = $200
Tulu received 6*$50 = $300
Kassa and Tegitu each received 5*$50 = $250
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Two numbers have a sum of 1,212 and a difference of 518. What are the two numbers?
guapka [62]

Answer:

The two numbers are

518

694

Step-by-step explanation:

As per requirements the two equations will be

X+Y=1212

X-Y=518

When we subtract these equations we get

X=1212-518

X=694

Now put the X value and find the Y value in any equation

X+Y= 1212

Y=1212-X

Where X = 694

Y=1212-694

Y=518

X=694 and Y=518

4 0
3 years ago
Algebra 2: Functions, graphing, and transformations.
erastovalidia [21]

Answer:

The answer is  “C” (Shifts left 3 units)

Step-by-step explanation:

To find the transformation, compare the function to the parent function and check to see if there is a horizontal or vertical shift, reflection about the x-axis or y-axis, and if there is a vertical stretch.

5 0
3 years ago
Which pair of angles are vertical angles?
Vitek1552 [10]
Answer is C. HMG and LMK
see attached picture to explain
Vertical angles are congruent and opposite of each other where two lines cross

8 0
2 years ago
What is the 57th term of the arithmetic sequence : 11,8,5,2
andriy [413]
I think its this <span> 14 - 3*57 = 14 - 171 = -157 </span>
4 0
3 years ago
Which description does NOT guarantee that a quadrilateral is a square?
Ivahew [28]
Let's go through the choices one by one

------------------------------------------
Choice A

If all sides are congruent, then this figure is a rhombus (by definition). If all angles are congruent, then we have a rectangle. Combine the properties of a rhombus with the properties of a rectangle and we have a square.

In terms of "algebra", you can think
rhombus+rectangle = square

Or you can draw out a venn diagram. One circle represents the set of all rhombuses; another circle represents the set of all rectangles. The overlapping region is the set of all squares. The overlapping region is inside both circles at the same time.

So we can rule out choice A. This guarantees we have a square when we want something that isn't a guarantee.

------------------------------------------
Choice B

If we had a parallelogram with perpendicular diagonals, then we can prove that we have a rhombus (all four sides congruent). However, we don't know anything about the four angles of this parallelogram. Are they congruent? We don't know. So we can't prove this figure is a rectangle. The best we can say is that it's a rhombus. It may or may not be a rectangle. There isn't enough info about the rectangle & square part.

This is why choice B is the answer. We have some info, but not enough to be guaranteed everytime.

------------------------------------------
Choice C

This is a repeat of choice A. Having "all right angles" is the same as saying "all angles congruent". This is because "right angle" is the same as saying "90 degrees". So we can rule out choice C for identical reasons as we did with choice A.

------------------------------------------
Choice D

As mentioned before in choice A, if we know that a quadrilateral is a rectangle and a rhombus at the same time, then the figure is also a square. This is always true, so we are guaranteed to have a square. We can cross choice D off the list.

------------------------------------------

Once again, the final answer is choice B


3 0
3 years ago
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