All categories

3 years ago

For stars in the main sequence, which color of stars tend to have higher absolute brightness?

Physics

2 answers:

PilotLPTM [1.2K]3 years ago

6 0

White star and dwarf

abruzzese [7]3 years ago

4 0

Answer:

from the higher to lower brightness: white, blue, yellow and red

Explanation:

a dwarf star has the lower brightness and absolutely hot temperature

You might be interested in

Technician A says that all components in the high voltage battery box are completely insulated from the rest of the vehicle for

blsea [12.9K]

Answer:

Technician A

Explanation:

The HV components include the cell, module, or battery pack terminals and any conductive parts attached to them. These components have to be isolated from other conductive (low-voltage) components of the battery pack, such as the module housing, the battery casing, or the cooling system.

Battery should be located I'm the trunk

5 0

4 years ago

Researchers are investigating whether people who exercise with a training partner have a greater increase, on average, in target

liubo4ka [24]

<u><em>[NOTE: THIS IS INCOMPLETE QUESTION. THE COMPLETE QUESTION: Researchers are investigating whether people who exercise with a training partner have a greater increase, on average, in targeted exercise intensity compared with people who exercise alone. Two methods of collecting data have been proposed. Method i: recruit volunteers who are willing to participate. Randomly assign each participant to exercise with a training partner or to exercise alone. Method ii: select a random sample of people from all the people who exercise at a community fitness center. Ask each person in the sample whether they use a training partner, and use the response to create the two groups.]</em></u>

In method I, the population generalization is almost random, hence it uses a random sample. In method II, the population generalization is less random, hence it uses a biased sample.

In terms of population generalization, the two methods differ. In method I where participants randomly assign each participant to exercise with a training partner or to exercise alone from the volunteers who are willing to participate, the sampling method is almost random as it includes people who are exercise regularly (in majority) and those who do not exercise regularly. Due to the randomized nature of the sample, the results can be applied to the entire population.

In method II where sampling is done by selecting a random sample of people from all the people who exercise at a community fitness center and determining if they use a training partner or exercise alone to create the two groups. As the people included in the sample are less random as they work out regularly at the fitness center. Hence, the sample is biased as it does not include any representation of people who do not work out regularly. The results cannot be used to apply to the entire population generalization.

Therefore, Population generalization is generalizing the population into two categories out of which one is more random in selection than the other.

Learn more about Population generalization, refer: brainly.com/question/26238937

#SPJ4

4 0

1 year ago

Two immersion heaters, A and B, are both connected to a 120.0-V supply. Heater A can raise the temperature of 1.00 L of water fr

Inessa05 [86]

Answer:

Ratio of resistance of heater A to resistance of heater B is 5.80

Explanation:

Consider C be the specific heat of water, R₁ and R₂ be the resistance of heater A and heater B respectively.

Given:

Mass of water in heater A, m₁ = 1 L

Mass of water in heater B, m₂ = 5.80 L

Initial temperature, T₀ = 20 ⁰C

Final temperature, T₁ = 90 ⁰C

Time, t = 5 min

Amount of heat required to raise the temperature of water by heaters A and B are given by:

Q₁ = m₁C(T₁ - T₀) and

Q₂ = m₂C(T₁ - T₀)

Ratio of power used by both the heaters A and B is:

$\frac{P_{1} }{P_{2} } =\frac{Q_{1} }{t} \times\frac{t}{Q_{2} }$

Since, time t, temperature difference(T₁ - T₀) and specific heat C are same for both the heaters A and B. So, the above equation becomes:

$\frac{P_{1} }{P_{2} } =\frac{m_{1} }{m_{2} }$ ...(1)

The relation to determine electrical power for both heaters A and B are:

$P_{1}=\frac{V^{2} }{R_{1} }$ and

$P_{2}=\frac{V^{2} }{R_{2} }$

Here V is the voltage applied to both the heaters and is equal.

So, the ratio of electrical power of heaters is:

$\frac{P_{1} }{P_{2} } =\frac{R_{2} }{R_{1} }$ ....(2)

But according to the problem, the electrical power is converted into the thermal power. So,equation (1) and (2) are equal. Hence,

$\frac{m_{1} }{m_{2} } =\frac{R_{2} }{R_{1} }$

Substitute the suitable values in the above equation.

$\frac{1 }{5.80 } =\frac{R_{2} }{R_{1} }$

$\frac{R_{1} }{R_{2} }=5.80$

6 0

3 years ago

A car of mass 1200 kg traveling westward at 30. m/s is slowed to a stop in a distance of 50. m by the car’s brakes. What was the

natka813 [3]

I believe that the answer is C. 11,000

5 0

3 years ago

Read 2 more answers

Convert the number from scientific into standard notation: 5.9 x 10-2

guapka [62]

Move the decimal point to:
Left : (if the exponent of ten is a negative number -) ... OUR CASE HERE (-2)
or to
Right : (if the exponent is positive +).

You should move the point as many times as the exponent indicates.
Do not write the power of ten anymore.

So, standard form is:
Two points to the left {Exponent of Ten is Negative (-2)}
0.059 ... (without the 10)

6 0

3 years ago