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Nimfa-mama [501]
3 years ago
14

Why does petrol vapour gets stucked into the carborator of thecar.

Physics
1 answer:
hammer [34]3 years ago
4 0

Answer:vapour gets stuckes into the carburetor when the car engine heat up with continuous acceleration and deceleration.

Explanation:Vapor lock occurs when the car engine gets heat up with continuous acceleration and deceleration. The automobile engine has to work harder during the hot summer days. An automobile engine runs hotter than usual in the stop-go traffic.. This extreme heat vaporizes the fuel in carburetor and fuel pump.

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Which is true of the buoyant force?
victus00 [196]

It acts in the upward direction.

8 0
3 years ago
What is a difference between newton’s laws of motion and einstein’s theory of relativity?newton’s laws are factual statements, w
Tom [10]
Einstein’s theory can found E = mc 2
Issac Newton was found universal gravitional (gravity) opinion.newton’s laws can be revised over time, but einstein’s theory of relativity
5 0
3 years ago
A automotive test driver travels due north in a prototype hybrid vehicle at 30 mi/h
Nikolay [14]

Answer:

Option A. 40 mi/h

Explanation:

To obtain the average speed of the vehicle, we'll begin by calculating the distance travelled by the vehicle in each case. This is illustrated below:

Case 1:

Speed = 30 mi/h

Time = 2 h

Distance =...?

Speed = Distance /Time

30 = Distance /2

Cross multiply

Distance = 30 × 2

Distance = 60 mi

Case 2:

Speed = 60 mi/h

Time = 1 h

Distance =...?

Speed = Distance /Time

60 = Distance /1

Cross multiply

Distance = 60 × 1

Distance = 60 mi

Finally, we shall determine the average speed of the vehicle as follow:

Total distance travelled = 60 + 60

Total distance travelled = 120 mi

Total time = 2 + 1

Total time = 3 h

Average speed =..?

Average speed = Total Distance travelled /Total time

Average speed = 120/3

Average speed = 40 mi/h

Therefore, the average speed of the vehicle is 40 mi/h

3 0
4 years ago
The terminal velocity of a person falling in air depends upon the weight and the area of the person facing the fluid. Find the t
DENIUS [597]

Answer:

terminal velocity is;

v = 117.54 m/s

v = 423.144 km/hr

Explanation:

Given the data in the question;

we know that, the force on a body due to gravity is;

F_g = mg

where m is mass and g is acceleration due to gravity

Force of drag is;

F_d = \frac{1}{2}pCAv²

where p is the density of fluid, C is the drag coefficient, A is the area and v is the terminal velocity.

Terminal velocity is reach when the force of gravity is equal to the force of drag.

F_g = F_d

mg =  \frac{1}{2}pCAv²

we solve for v

v = √( 2mg / pCA )

so we substitute in our values

v = √( [2×(86 kg)×9.8 m/s² ] / [ 1.21 kg/m³ × 0.7 × 0.145 m²] )

v = √( 1685.6 / 0.122015 )

v = √( 13814.6949 )

v  = 117.54 m/s

v = ( 117.54 m/s × 3.6 ) = 423.144 km/hr

Therefore terminal velocity is;

v = 117.54 m/s

v = 423.144 km/hr

5 0
3 years ago
(b) If the object is at 330 feet and its instantaneous velocity is 3 feet per minute at 30 minutes, what is the approximate posi
ELEN [110]

Answer:

The final position is 36 feet.

Explanation:

initial position, d = 330 feet

speed, v = 3 feet per minute

time, t = 30 minute

now the time is 32 minute

time interval = 2 minute

So, the distance in 2 minutes is

d' = 2 x 3 = 6 feet

So, the final position is

D = 30 + 6 = 36 feet

8 0
3 years ago
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