Answer:
The rate at which the pump moves oil is 1 m³/s
Explanation:
Assumptions:
- there is steady-state flow
- oil and water are incompressible
- first fluid is water, second fluid is oil and third fluid is the mixture of oil and water.
where;
ρ is the fluid density
Q is the volumetric flow rate
Substitute in Q₃ in equation i
divide through by ρ₁
Make Q₂ the subject of the formula
Therefore, the rate at which the pump moves oil is 1 m³/s
Answer:
20 N exerts no torque about the pivot.
14 N exerts a counterclockwise torque of 14 * .3 = .42 N-m
6 exerts a clockwise torque of 6 * .7 = .42 N-m
The meter stick will not turn because there is no net torque on the meter stick.
Convection is the right answer!!!
Ps.: hope this helps!!!!
Answer:
The magnitude of the magnetic field at the center of the loop is 3.846 x 10⁻⁵ T.
Explanation:
Given;
number of turns of the flat circular loop, N = 18 turns
radius of the loop, R = 15.0 cm = 0.15 m
current through the wire, I = 0.51 A
The magnetic field through the center of the loop is given by;
Where;
μ₀ is permeability of free space = 4π x 10⁻⁷ m/A
Therefore, the magnitude of the magnetic field at the center of the loop is 3.846 x 10⁻⁵ T.
Answer:
Explanation:
Total distance covered = 25 + 15 = 40 m
Total time = 15 + 8 = 23 s
Average speed = total distance covered / total time
= 40 / 23
= 1.74 m / s
Total displacement = 25 - 15 = 10 m
Total time = 15 + 8 = 23 s
Average velocity = total displacement / total time
= 10 / 23
= .434 m / s to the right .
