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Gekata [30.6K]
2 years ago
15

I’m confused how do you right that in OZ someone please help I have to turn it in

Physics
1 answer:
RUDIKE [14]2 years ago
8 0
300g is what that is on which is equal to 10.58oz
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The equation that is used to solve second law problems is # F= ma.
maw [93]
F= Force 
M=Mass
A= acceleration 
F=N 
Mass= in grams or kilo grams (mostly kg)
A= m/s 

8 0
3 years ago
What will happen to an object's wavelength as the object moves towards you?
Ilia_Sergeevich [38]
The wavelength will get shorter
5 0
3 years ago
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Forces always act in pairs? True or false
nasty-shy [4]

Answer:

True

Explanation:

Just as Isaac Newton says, "For every action, there is an equal and opposite reaction."

7 0
3 years ago
Beings on spherical asteroid have observed that a large rock is approaching their asteroid in a collision course. At 7514 km fro
luda_lava [24]

Answer:

c. 4.582\times10^{21} kg

Explanation:

r_{i} = Initial distance between asteroid and rock = 7514 km = 7514000 m

r_{f} = Final distance between asteroid and rock = 2823 km = 2823000 m

v_{i} = Initial speed of rock = 136 ms⁻¹

v_{f} = Final speed of rock = 392 ms⁻¹

m = mass of the rock

M = mass of the asteroid

Using conservation of energy

Initial Kinetic energy of rock + Initial gravitational potential energy = Final Kinetic energy of rock + Final gravitational potential energy

(0.5) m v_{i}^{2} - \frac{GMm}{r_{i}} = (0.5) m v_{f}^{2} - \frac{GMm}{r_{f}} \\(0.5) v_{i}^{2} - \frac{GM}{r_{i}} = (0.5) v_{f}^{2} - \frac{GM}{r_{f}} \\(0.5) (136)^{2} - \frac{(6.67\times10^{-11}) M}{(7514000)} = (0.5) (392)^{2} - \frac{(6.67\times10^{-11}) M}{(2823000)} \\M = 4.582\times10^{21} kg

8 0
3 years ago
A box is being pulled to the right. What is the magnitude of the Kinect frictional force?
Anna35 [415]
The answer to this question is A - 25 N
3 0
2 years ago
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