Answer:
Angular velocity of tire ![\approx 66.67\ s^{-1}](https://tex.z-dn.net/?f=%5Capprox%2066.67%5C%20s%5E%7B-1%7D)
Explanation:
Given:
Diameter of tire of an automobile =75.0 cm
Linear velocity of automobile = 90.0 km/hr
To find angular velocity of tire.
Diameter of tire in meters = ![75\ cm \times \frac{1\ m}{100\ cm}= 0.75\ m](https://tex.z-dn.net/?f=75%5C%20cm%20%5Ctimes%20%5Cfrac%7B1%5C%20m%7D%7B100%5C%20cm%7D%3D%200.75%5C%20m)
Radius of tire = ![\frac{1}{2}\times diameter=\frac{1}{2}\times 0.75\ m = 0.375\ m](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20diameter%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%200.75%5C%20m%20%3D%200.375%5C%20m)
Linear velocity in meters per second = ![\frac{90\ km}{1\ hr}\times \frac{1000\ m}{1\ km}\times \frac{1\ hr}{3600\ s}= 25\ m/s](https://tex.z-dn.net/?f=%5Cfrac%7B90%5C%20km%7D%7B1%5C%20hr%7D%5Ctimes%20%5Cfrac%7B1000%5C%20m%7D%7B1%5C%20km%7D%5Ctimes%20%5Cfrac%7B1%5C%20hr%7D%7B3600%5C%20s%7D%3D%2025%5C%20m%2Fs)
Angular velocity
is given by :
![\omega=\frac{v}{r}](https://tex.z-dn.net/?f=%5Comega%3D%5Cfrac%7Bv%7D%7Br%7D)
where
represents linear velocity and
represents radius of tire.
Plugging in values.
![\omega=\frac{25\ m/s}{0.375\ m}](https://tex.z-dn.net/?f=%5Comega%3D%5Cfrac%7B25%5C%20m%2Fs%7D%7B0.375%5C%20m%7D)
∴
(Answer)
The solute would then sink to the bottom and would not dissolve
The correct answer that would best complete the given statement above would be the term KILOCALORIE. A KILOCALORIE is the amount of heat needed to raise the temperature of one kilogram of water one degree centigrade. On the other hand, t<span>he amount of heat needed to raise the temperature of one gram of water one Centigrade degree is calorie. Hope this answer helps.</span>
A! Good luck on your test!