3 years ago

Order of operations how do you solve 10/5*(7-2+4^2)

Mathematics

1 answer:

kvv77 [185]3 years ago

3 0

10/5 =2
7-2+4^2 =5+16=21
2*21=42

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four cards numbered 1, 5, 8, and 9 are placed in a bag. A card is drawn at random and then replaced. Then a card is drawn at ran

Vadim26 [7]

Answer:

1/16

Step-by-step explanation:

Four cards numbered (1, 5, 8,9)

Given the sample space S= 4

1.The first selection with replacement

Probability of picking a 9= 1/4

2. Second selection, probability of picking a 9= 1/4

Hence the probability that both cards drawn have the number 9.

Is = (1/4)*(1/4)= 1/16

6 0

3 years ago

Kindly solve this question 6 too !!

Shkiper50 [21]

Answer:

$x=1$

Step-by-step explanation:

$~~~~~x = \dfrac{1}{2 - \dfrac 1{2-\dfrac{1}{2-x}}}\\\\\\\implies x = \dfrac{1}{2 - \dfrac 1{\dfrac{4-2x-1}{2-x}}}\\\\\\\implies x= \dfrac{1}{2 - \dfrac{2-x}{3-2x}}\\\\\\\implies x = \dfrac{1}{\dfrac{6-4x-2+x}{3-2x}}\\\\\\\implies x = \dfrac{3-2x}{4-3x}\\\\\\\implies 4x -3x^2 = 3-2x\\\\\\\implies 3x^2 -4x +3-2x = 0\\\\\\\implies 3x^2 -6x +3 = 0\\\\\\\implies 3(x^2 -2x +1) =0\\\\\\\implies x^2 -2x +1 = 0\\\\\\\implies (x-1)^2 = 0\\\\\\\implies x -1 = 0\\\\\\\implies x = 1$