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Arisa [49]
2 years ago
7

-11 2/3 x (-4 1/5 ) = any help???

Mathematics
1 answer:
rjkz [21]2 years ago
7 0

Answer:

did this as multiplication

=49

Step-by-step explanation:

-35/3 * -21/5 = 735/15  =49

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In a survey of randomly selected 3,900 family-owned businesses with revenues exceeding $1 million a year, it was found that 1,91
Maurinko [17]

Answer:

a) The 90% confidence interval to estimate the proportion of family-owned businesses without strategic business plans is (0.4768, 0.5032). This means that we are 90% sure that the true proportion of all family-owned businesses without strategic business plans is between these two values.

b) Wider

Step-by-step explanation:

Question a:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

In a survey of randomly selected 3,900 family-owned businesses with revenues exceeding $1 million a year, it was found that 1,911 of them had no strategic business plan.

This means that n = 3900, \pi = \frac{1911}{3900} = 0.49

90% confidence level

So \alpha = 0.1, z is the value of Z that has a p-value of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.49 - 1.645\sqrt{\frac{0.49*0.51}{3900}} = 0.4768

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.49 + 1.645\sqrt{\frac{0.49*0.51}{3900}} = 0.5032

The 90% confidence interval to estimate the proportion of family-owned businesses without strategic business plans is (0.4768, 0.5032). This means that we are 90% sure that the true proportion of all family-owned businesses without strategic business plans is between these two values.

Question b:

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

The higher the confidence level, the higher the value of z, thus the higher the margin of error and the interval is wider. Thus, a 99% confidence interval is wider than a 90% confidence interval.

3 0
2 years ago
Help<br> Please thanks!!!!
expeople1 [14]
6 i believe but im not sure
5 0
3 years ago
The reacttimes data set has 50 observations of human reaction times to a physical stimulus. The reaction times are named times a
scoundrel [369]

Solution: The formula for mean is:

Mean=\frac{\sum x}{n}

Where:

\sum x is the sum of given observations

n is the number of observations

\sum x=87.12

n=50

\therefore Mean =\frac{87.12}{50}= 1.74 rounded to two decimal places

To find the median, we need to first arrange the data in ascending order but we are already given the data in ascending order.

Therefore, the median is:

Median=\left(\frac{n+1}{2} \right)^{th} item

                  =\left(\frac{51}{2} \right)^{th} item

                  =25.5^{th} item

                  =1.52+0.5(1.54-1.52)

                  =1.52+0.01

                  =1.53

Therefore, the median = 1.53

4 0
3 years ago
Find sum or difference.<br><br>-1/2 + 1/3
Free_Kalibri [48]
2/5 is the answer unless your multiplying
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3 years ago
Anyone else trying to study but t i k t o k is being addicting
dlinn [17]

Step-by-step explanation:

yes I am how about you, I always get stuck on my assignments

8 0
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