Ask question

Ask question

All categories

3 years ago

14

Combining like terms 2a+1+9a+7

2 answers:

fiasKO [112]3 years ago

7 0

Answer:11a+8

Step-by-step explanation:

Masja [62]3 years ago

5 0

Answer:

11a+8

Step-by-step explanation:

Combine like terms, so you add 2a and 9a to get 11a, then add 1 and 7 to get 8

You might be interested in

1. A line passes through the point (2, k) and (4k, 5) and has a slope of 1/2 . Find the value of k.

Doss [256]

$(\stackrel{x_1}{2}~,~\stackrel{y_1}{k})\qquad (\stackrel{x_2}{4k}~,~\stackrel{y_2}{5}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{5}-\stackrel{y1}{k}}}{\underset{run} {\underset{x_2}{4k}-\underset{x_1}{2}}}~~= ~~\stackrel{\stackrel{m}{\downarrow }}{\cfrac{1}{2}} \\\\\\ 10-2k=4k-2\implies 10=6x-2\implies 12=6k\implies \cfrac{12}{6}=k\implies 2=k$

5 0

3 years ago

Please help me do this 2 assignments (:

amm1812

4)120
5) -24a¹⁰
………………

8 0

3 years ago

Consider this exponential equation:

ioda

Step-by-step explanation:

F( <em>x</em><em> </em><em>)</em><em> </em><em>=</em><em> </em><em>5</em><em> </em><em>(</em><em>3</em><em>)</em><em> </em><em>^</em><em> </em><em>x</em>

<em>Y</em><em> </em><em>intercept</em><em> </em>

<em>Let</em><em> </em><em>x</em><em> </em><em>=</em><em> </em><em>0</em>

<em>f</em><em>(</em><em>0</em><em>)</em><em> </em><em>=</em><em> </em><em>5</em><em>×</em><em> </em><em>3</em><em> </em><em>^</em><em> </em><em>0</em>

<em>f</em><em>(</em><em>0</em><em> </em><em>=</em><em> </em><em>5</em><em> </em><em>×</em><em> </em><em>1</em>

<em>f</em><em>(</em><em>0</em><em>)</em><em> </em><em>=</em><em> </em><em>5</em>

<em>X</em><em> </em><em>intercept</em><em> </em>

<em>let</em><em> </em><em>y</em><em> </em><em>=</em><em> </em><em>o</em>

<em>0</em><em> </em><em>=</em><em> </em><em>5</em><em> </em><em>×</em><em> </em><em>3</em><em> </em><em>^</em><em>x</em>

<em>No</em><em> </em><em>x</em><em> </em><em>intercept</em><em>/</em><em> </em><em>zero</em>

<em>therefore</em><em> </em>

<em>Vertical</em><em> </em><em>intercept</em><em> </em><em>(</em><em>0</em><em>;</em><em> </em><em>5</em><em>)</em>

<em>Domain</em><em> </em><em>XER</em>

<em>▪︎</em><em>this</em><em> </em><em>refer</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>values</em><em> </em><em>of</em><em> </em><em>X</em>

4 0

3 years ago

The median of a continuous random variable having distribution function F is that value m such that F(m) = 1/2 . That is, a rand

neonofarm [45]

Answer:

Step-by-step explanation:

To find median and mode for

a) In a uniform distribution median would be

(a+b)/2 and mode = any value

b) X is N

we know that in a normal bell shaped curve, mean = median = mode

Hence mode = median = $\mu$

c) Exponential with parameter lambda

Median = $\frac{ln2}{\lambda }$

Mode =0

7 0

3 years ago

Need help please! Will give it to the brainliest. Which expression models the bacterium's volume? Picture is below.

Tomtit [17]

The expression C. $\pi (1)^{2} (0.5)$ cubic $\mu \mathrm{m}$ represents the bacterium's volume.

Step-by-step explanation:

Step 1:

The E. Coli bacterium is in the shape of a cylinder.

The volume of a cylinder is given by multiplying π with the square of the radius (r²) and the height of the cylinder.

The volume of a cylinder, $V=\pi r^{2} h.$

In the given diagram, E. Coli has a radius of 1 $\mu \mathrm{m}$ and a height of 0.5 $\mu \mathrm{m}$ .

Step 2:

By substituting the values in the equation, we get

The volume of the E. Coli bacterium $= \pi (1)^{2} (0.5)$ cubic $\mu \mathrm{m}$ .

This is option C.

7 0

3 years ago