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horrorfan [7]
4 years ago
14

Combining like terms 2a+1+9a+7

Mathematics
2 answers:
fiasKO [112]4 years ago
7 0

Answer:11a+8

Step-by-step explanation:

Masja [62]4 years ago
5 0

Answer:

11a+8

Step-by-step explanation:

Combine like terms, so you add 2a and 9a to get 11a, then add 1 and 7 to get 8

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What is the smallest whole number to the right of 3.52? <br>​
igor_vitrenko [27]
I got the answer of 4
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3 years ago
Find the the angles of CBD
Serhud [2]

Answer:

125 degrees.

Step-by-step explanation:

m < CBD = m < A + m < C ( by the External Angle of a Triangle theorem).

=  58 + 67 = 125 degrees.

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3 years ago
Read 2 more answers
Use Theorem 2.1.1 to verify the logical equivalence. Give a reason for each step. -(pv –q) v(-p^q) = ~p
sertanlavr [38]

Answer:

The statement \lnot(p\lor\lnot q)\lor(\lnot p \land \lnot q) is equivalent to \lnot p, \lnot(p\lor\lnot q)\lor(\lnot p \land \lnot q) \equiv \lnot p

Step-by-step explanation:

We need to prove that the following statement \lnot(p\lor\lnot q)\lor(\lnot p \land \lnot q) is equivalent to \lnot p with the use of Theorem 2.1.1.

So

\lnot(p\lor\lnot q)\lor(\lnot p \land \lnot q) \equiv

\equiv (\lnot p \land \lnot(\lnot q))\lor(\lnot p \land \lnot q) by De Morgan's law.

\equiv (\lnot p \land q)\lor(\lnot p \land \lnot q) by the Double negative law

\equiv \lnot p \land (q \lor \lnot q) by the Distributive law

\equiv \lnot p \land t by the Negation law

\equiv \lnot p by Universal bound law

Therefore \lnot(p\lor\lnot q)\lor(\lnot p \land \lnot q) \equiv \lnot p

4 0
3 years ago
4. The table below represents some points of a linear function. What is the
joja [24]

Answer:

The rate of change for this function or slope is 2

Step-by-step explanation:

3 0
3 years ago
Which are the maximum values ? I will add a picture please help
Alik [6]

Answer:

58 at the point (9,8)

7 at the point (1, 1)

Step-by-step explanation:

The maximum points will be found in the vertices of the region.

Therefore the first step to solve the problem is to identify through the graph, the vertices of the figure.

The vertices found are:

(1, 10)

(1, 1)

(9, 5)

(9, 8)

We look for the values of x and y belonging to the region, which maximize the objective function f(x, y) = 2x + 5y. Therefore we look for the vertices with the values of x and y higher.

(1, 10), (9, 5), (9, 8)

Now we substitute these points in the objective function and select the one that produces the highest value for f (x, y)

f(1, 10) = 2(1) + 5(10) = 52\\\\f(9, 5) = 2(9) + 5(5) = 43\\\\f(9, 8) = 2(9) + 5(8) = 58

The point that maximizes the function is:

(9, 8) with f(9, 8) = 58

Then the value that produces the minimum of f(x, y) is (1, 1)

f(1, 1) = 2(1) + 5(1) = 7

5 0
3 years ago
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