How do you solve number 13 and 14?
1 answer:
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So if it is 3x^2+4x=2 then
set one side to zero
subtract 2 from both sides
3x^2+4x-2=0
this is not factorable by normal means so use quadratic formula which is if you have the equation in ax^2+bx+c=0 form you can solve for x if you put it into this equation quadratic formula
so if you were to input it into this equation you would get
a=3
b=4
c=-2
the solution is
the answer is C
set one side to zero
subtract 2 from both sides
3x^2+4x-2=0
this is not factorable by normal means so use quadratic formula which is if you have the equation in ax^2+bx+c=0 form you can solve for x if you put it into this equation quadratic formula
a=3
b=4
c=-2
the solution is
the answer is C