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3 years ago

How do you solve number 13 and 14?

Mathematics

1 answer:

Ulleksa [173]3 years ago

3 0

This is what I got hope u get it right gl

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The equation (x-6)^2/16 + (y+7)^2/4 = 1 represents an ellipse. What are the vertices of the ellipse?

topjm [15]

Answer:

The correct option is C.

Step-by-step explanation:

The given equation is

$\frac{(x-6)^2}{16}+\frac{(y+7)^2}{4}= 1$

It can be rewritten as

$\frac{(x-6)^2}{4^2}+\frac{(y+7)^2}{2^2}= 1$ .....(1)

The standard form of an ellipse is

$\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}= 1$ ....(2)

Where (h,k) is center of the ellipse.

If a>b, then the vertices of the ellipse are $(h\pm a, k)$ .

From (1) and (2) we get

$h=6,k=-7,a=4,b=2$

Since a>b, therefore the vertices of the ellipse are

$(h+a, k)=(6+4,-7)\Rightarrow (10,-7)$

$(h-a, k)=(6-4,-7)\Rightarrow (2,-7)$

The vertices of the given ellipse are (10, –7) and (2, –7). Therefore the correct option is C.

5 0

2 years ago

Read 2 more answers

Which power has a value of 1?

kogti [31]

X^0=1
5^0=1

1^n=1
answer is 1^4 and 5^0

4 0

3 years ago

If log10 y = 2. what does y equal?

lys-0071 [83]

Answer:

$log_{10} (100) = 2$

Step-by-step explanation:

Here, the given expression is:

$log_{10} (y) = 2$

Now, by logarithm rules, we know

if $log_{b}(x) = z$

, then x = $b^{z}$

Comparing here, b = 10 and z = 2

⇒ y = $10^{2} = 100$

or, $log_{10} (100) = 2$

6 0

3 years ago

Solve 3(x-4)=-5 for x

makvit [3.9K]

Answer:

x=7/3

Step-by-step explanation:

3(x-4)=-5

3x-12=-5

3x=7

x=7/3

8 0

2 years ago

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Https://www.blooket.com/play?id=658244

Paladinen [302]

Answer:

Step-by-step explanation:

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2 years ago