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QveST [7]
2 years ago
7

How do you solve number 13 and 14?

Mathematics
1 answer:
Ulleksa [173]2 years ago
3 0
This is what I got hope u get it right gl

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Just to ensure I'm doing this method right, (for clarification)
EleoNora [17]
You are right i tried it and i got it right
4 0
3 years ago
3(12)=2(y-1) <br> *plzz answer my question*
Leona [35]

Step-by-step explanation:

3(12)=2(y-1)

36=2y-2

36+2=2y

38=2y(<em>Divide</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em><em>by</em><em> </em><em>two</em><em>)</em>

y=19

7 0
2 years ago
X = y - 3
mojhsa [17]
Hello,
{x=y-3
{x+3y=13;

{x=y-3
{y-3+3y=13;


{x=y-3
{4y=13+3;

{x=y-3
{4y=16;

{x=y-3
{y=16:4=4;

{x=4-3=1
{y=4;

{x=1
{y=4

the solution to the system of equations is (1,4)

Bye :-)
8 0
3 years ago
a group of students decided to collect as many paise (1/100 RS.) from each member of the group as is the number of members. If t
Softa [21]

Answer:

Let the no. Of members be x

Rs. 59.29 = 5929 paise

5929/x = x

x^2 = 5929

Therefore x = 77

No. Of members = 77

Hope this helps!

8 0
2 years ago
{(-9,3) (5,-6) (3,-1), (-6,5), ?}Which ordered pair can replace the missing value and make the set if ordered pairs NOT a functi
Nookie1986 [14]
\text{Slope}=\frac{-1--6}{3-5}=\frac{5}{-2}\begin{gathered} y-y_1=\frac{5}{-2}(x-x_1) \\  \\ y--6=\frac{5}{-2}(x-5) \\  \\ -2(y+6)=5(x-5) \\ -2y-12=5x-25 \\ 5x+2y=25-12 \\ 5x+2y=13 \end{gathered}

The missing values are (-6, -9) ( The last option)

Explanation:

x= - 6 has already produced the value of y as 5, the only pair in the given option the make the given ordered pairs NOT to be a function is (-6, -9) since it will give the value of y to be - 9.

4 0
1 year ago
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