Answer:
Step-by-step explanation:
The common difference (d) can be found using the first and 4th terms:
a1 = 3
a4 = a1 +d(4 -1)
-9 = 3 +3d . . . . . simplify
-3 = 1 + d . . . . . . divide by 3
-4 = d . . . . . . . . . subtract 1
Then ...
x = a1 + d = 3 -4 = -1
y = x + d = -1 -4 = -5
The values of x and y are -1 and -5, respectively.
Answer:
$46
Step-by-step explanation:
The rate of the passenger train is 81.67 MPH and the rate of the freight train is 66.67 MPH.
<h3>What is a linear equation?</h3>
It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.
If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.
We have:
The distance traveled by passenger train = 245 miles
The distance traveled by freight train = 245 miles
The time takes for both trains is the same.
Let's suppose the rate of the passenger train is x and the rate of the freight train is y;
As we know,
Distance = speed×time
245/x = 200/y
200x = 245y
200x - 245y = 0 ..(1)
x = 15 + y ..(2)
Equations (1) and (2) represent the situation.
After solving equations (1) and (2):

Thus, the rate of the passenger train is 81.67 MPH and the rate of the freight train is 66.67 MPH.
Learn more about the linear equation here:
brainly.com/question/11897796
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It’s Q
Q = 55%
Hope this helps you!!!
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