1.) set up a w_k_u chart
2.) in the w column write in on top and mi in the bottom like this
w_K_U
in_
mi_
then in the k column write 2 for in and 15 for mi
W_K_U
in_2_
mi_15_
then in the U column, you write 7 for in and x for mi
W_K_U
in_2_7
mi_15_x
then cross multiply: 2x = 15(7)
multiply 15 times 7 which is 105
2x=105
divide 2x by 2
x=105
answer 105
20.12… squared equals 405
Square root of 405
/405
/81 x 5
9 / 5
9 Times Square root of 5 :)
In this problem, since we are trying to find Sam's monthly net income, we just need to multiply his weekly net income (which is after all the deductions come out) by how many times he gets paid! Because he gets paid 4 times, we just need to multiply $654.48 by 4! The you should get an answer of $2617.92, which is Sam's monthly net income!
Answer:
y = 0
Step-by-step explanation:
It is always a good idea to look at the question and make some observations about it. Here, you might observe ...
- all of the bases are powers of 3: 243 = 3^5; 9 = 3^2
- y is a factor of every exponent
The latter observation is important, because it means that when y=0, every exponential expression has a value of 1. Hence y = 0 is a solution.
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To solve the equation, you can write it in terms of powers of 3.
(3^5)^(-y) = (3^-5)^(3y)·(3^2)^(-2y)
3^(-5y) = 3^(-15y)·3^(-4y)
3^(-5y) = 3^(-19y)
-5y = -19y . . . . . . . . equating exponents; equivalent to taking log base 3
14y = 0 . . . . . . . . . . add 19y
y = 0 . . . . . . . . . . . one solution
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The rules of exponents we used are ...
(a^b)(a^c) = a^(b+c)
(a^b)^c = a^(bc)
1/a^b = a^-b
Answer:
Step-by-step explanation:
Try and become familiar with a program like Desmos. It will do wonderful things for you.
I have graphed
Red: y = -2x + 5 (The 5 is the y intercept. For this question it could be anything.
Blue: y = - 4x + 5 Same note as above.
