Answer:
Option A.
Step-by-step explanation:
The given question is incomplete. Here is the complete question.
P(n) models the price (in dollars) of a pack of n bulbs at a certain store.
When does the price of a pack increase faster ?
n 4 10 12
P(n) 12 25 28
When does the price of a pack increase faster ?
A. Between 4 and 10 bulbs
B. Between 10 and 12 bulbs
C. The price increases at the same rat over both the intervals.
To solve this question we will find the rate of increase in the prices per pack in the given intervals.
From n = 4 to n = 10
Rate of increase in price = 
= 
= 2.166 ≈ $2.17 per pack
From n = 10 to n = 12
Rate of increase in price = 
=
= $1.5 per pack
Therefore, price per pack increases faster between n = 4 and n = 10 as compared to n = 10 to n = 12.
Option A is the answer.
42 packages.
1,008 divided by 24=42
Hope that helps! :)
Answer:
The probability is 1/3, or in percent form, 33.3%.
Step-by-step explanation:
First, add up all the marbles. 3 plus 2 plus 1 equals 6 total marbles.
There are 2 yellow marbles out of 6 total marbles. Make it a fraction: 2/6.
Simplify the fraction by dividing by 2, to get 1/3, which is 33.3%.
Hope this helps! Feel free to give me Brainliest if you feel this helped. Have a good day, and good luck on your assignment. :)
5. 1,000,000
6. 9,300
7. 5,070
8. 5, 280
9. 810
10. 220
11. 44,770
12. 76, 000
Those are a few answers for you. Try looking back at your notes (If you copied any) to figure out your problems :)
Answer:
f(x) = 3x^2 - 12x - 36.
Step-by-step explanation:
f(x) =3 /2(x - 2)^2 - 24
f(x) = 3/2 (x^2 - 4x + 4) - 24
f(x) = 3/2 x^2 - 6x + 6 - 24
f(x) = 3/2 x^2 - 6x - 18
Multiply through by 2:
f(x) = 3x^2 - 12x - 36.