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3 years ago

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In a bag there are 3 red marbles, 2 yellow marbles, and 1 blue marble. what is the probability in simplest form of a yellow marb

le being selected on the first draw.

1 answer:

dangina [55]3 years ago

5 0

Answer:

The probability is 1/3, or in percent form, 33.3%.

Step-by-step explanation:

First, add up all the marbles. 3 plus 2 plus 1 equals 6 total marbles.

There are 2 yellow marbles out of 6 total marbles. Make it a fraction: 2/6.

Simplify the fraction by dividing by 2, to get 1/3, which is 33.3%.

Hope this helps! Feel free to give me Brainliest if you feel this helped. Have a good day, and good luck on your assignment. :)

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aniked [119]

$\huge{\sf \left[{x-2y\atop 6x-2z}\:\:\:{4y-3\atop 2y-z}\right]=\left[{-3\atop 4}\:\:\:{5\atop 3}\right]}$

Creating equations

$\\ \sf\longmapsto x-2y=-3\dots(1)$

$\\ \sf\longmapsto 4y-3=5\dots(2)$

$\\ \sf\longmapsto 6x-2z=4\dots(3)$

$\\ \sf\longmapsto 2y-z=3\dots(3)$

From eq(2)

$\\ \sf\longmapsto 4y-3=5$

$\\ \sf\longmapsto 4y=5+3$

$\\ \sf\longmapsto 4y=8$

$\\ \sf\longmapsto y=\dfrac{8}{4}$

$\\ \bf\longmapsto y=2$

Put the value in eq(1)

$\\ \sf\longmapsto x-2y=-3$

$\\ \sf\longmapsto x=-3+2y$

$\\ \sf\longmapsto x=-3+2(2)$

$\\ \sf\longmapsto x=-3+4$

$\\ \bf\longmapsto x=1$

Put the value in eq(4)

$\\ \sf\longmapsto 2y-z=3$

$\\ \sf\longmapsto z=2y-3$

$\\ \sf\longmapsto z=2(2)-3$

$\\ \sf\longmapsto z=4-3$

$\\ \bf\longmapsto z=1$

8 0

3 years ago

The frame is a rectangle that’s 16 inches by 20 inches. The craft store has 7 feet of orange ribbon. Is that enough ribbon for L

Nutka1998 [239]

Hi!

Imagine a rectangle with a width of 20 inches, and a height of 16. Find the length around the rectangle (the perimeter).

16+20+16+20=72

There are 12 inches in a feet. How many feet are in 72 inches?

72/12=6

Lana needs 6 feet of ribbon. She bought 7 feet.

7-6=1

It is enough ribbon.
1 foot will be leftover.

Hope this helps! :)
-Peredhel

5 0

3 years ago

Find the slope of the line passing through the following points: (-12, -56), (-57,39).

Gnoma [55]

$(\stackrel{x_1}{-12}~,~\stackrel{y_1}{-56})\qquad (\stackrel{x_2}{-57}~,~\stackrel{y_2}{39}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{39}-\stackrel{y1}{(-56)}}}{\underset{run} {\underset{x_2}{-57}-\underset{x_1}{(-12)}}} \implies \cfrac{39 +56}{-57 +12} \implies \cfrac{ 95 }{ -45 } \implies {\Large \begin{array}{llll} - \cfrac{19 }{ 9 } \end{array}}$

3 0

1 year ago

Read 2 more answers

PLEASE HELP ME OUT AND MAKE SURE TO SHOW YOUR WORK!!!! PLEASEEEEE

madreJ [45]

Answer:

1. 15

2. 16

3. 46

4. 59

Step-by-step explanation:

1. 44+30=74, 89-74=15

2. 90-74=16

3. 180-134=46

4. angles like that are the same

5 0

3 years ago

Read 2 more answers

Please help very urgent i have like 2 mins to submit this and idk the answer. Thank you!<br>

Novosadov [1.4K]

Answer:

$\sqrt{949$

Step-by-step explanation:

difference in x = 7

difference in y = -30

using Pythagoras, distance = $\sqrt{x^{2} +y^{2} }$ = $\sqrt{7^{2} +30^{2} }$ = $\sqrt{949$

(but I don't understand what the nearest tenth part means)

8 0

3 years ago