The interest earned in 5 years would be $270
<u>Explanation:</u>
Given:
Principal, P = $1800
Rate of interest, r = 3%
Time, t = 5 years
Simple interest, I = ?
We know,

On substituting the value we get

Therefore, interest earned in 5 years would be $270
Answer:
a^2 + b^2 = c^2
Step-by-step explanation:
a^2 + b^2 = c^2
Answer:

Step-by-step explanation:
We want to simplify:

We rewrite the expression under the radical sign to obtain:

We split the expression under the radical sign to get:

Recall that:

This implies that:

Therefore 
Answer:
Step-by-step explanation:
Given that a large mixing tank initially holds 400 gallons of water in which 70 pounds of salt have been dissolved. Pure water is pumped into the tank at a rate of 4 gal/min, and when the solution is well stirred, it is then pumped out at the same rate.
Let Q(t) be the quantity of salt at time t.
Q(0) = 70 pounds
Inflow of water = outflow = 4 gal/min
So resulting volume of tank at time t = 400 gallons
Rate of change of salt = inflow - outflow
= 0 - 
i.e. 
This is a variable separable equation

Use when t =0 Q = 70
A =70
So A(t) = Q(t) =
and
A(0) = Q(0) = 70 lbs.
Answer:
x = 15
y = 15√3
Step-by-step explanation:
This is a special right triangle with angle measures 30° 60° 90°
The side lengths should be x 2x x√3
If the measure of hypotenuse 30 then the side length that sees 30° should be half of it so x = 15 and y = 15√3