Help please!!!!!!!!!!!

Solve for x in this equation: 3/4 + l 5-x| = 13/4 There are multiple other questions as well

omeli [17]

1. 3/4
2. im not sure if it means after taking away 3/4, but if it is, its 10/4

x=10/4 and -30/4 i believe, im not too good with fractions, sorry if its wrong :((

7 0

3 years ago

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Write any 4 laws of exponents.

emmainna [20.7K]

$\rule{50}{1}\large\blue\textsf{\textbf{\underline{Question:-}}}\rule{50}{1}$

Write any 4 laws, or properties, of exponents.

$\rule{50}{1}\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}$

$\Large\text{Law number 1:-}$

$\Large\text{$a^n*a^m=a^{n+m}$}$

$\Large\text{It states that:-}$

When we multiply together numbers with the same base,

we add the exponents.

$\Large\text{Law number 2:-}$

$\Large\text{$a^m:a^n=a^{m-n}$}$

$\Large\text{It states that:-}$

When we divide numbers with the same base, we

subtract the exponents.

$\Large\text{Law number 3:-}$

$\Large\text{$(\displaystyle\frac{x}{y}) ^n=\frac{x^n}{y^n}$}$

$\Large\text{It states that:-}$

If we have a fraction to a power, we raise the numerator and

the denominator to that power.

And then last but not least,

$\Large\textit{Law number 4:-}$

$\Large\text{$a^{-m} =\displaystyle\frac{1}{a^m}$}$

$\Large\text{It states that:-}$

If we have a number with a negative exponent, we flip it over.

<h3>Good luck with your studies.</h3>

#TogetherWeGoFar

$\rule{50}{1}\smile\smile\smile\smile\smile\smile\rule{50}{1}$

6 0

3 years ago

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HELP PLEASE must show work I have the answer just need to show work

Kazeer [188]

Answer:

Step-by-step explanation:

To solve these equations involving variables and exponents we need to follow these steps.

1) We need to find out the factor that is common in the equation.

2) After taking common, solve the equation. We can add or subtract only those values that have same bases.

1) $8+6x^4$

here we can see, both numbers are divisible by 2, so taking 2 common

$=2(8/2 + 6x^4/2)\\= 2(4 + 3x^4)$

It cannot be further simplified because both number donot have same bases.

3. $4n^9 + 12 n$

We can take 4n common

$=4n(4n^9/4n + 12 n/4n)\\=4n(n^8 + 3)$

5. -12a -3

Here -3 cam be taken common

= -3(-12a/-3 -3/-3)

= -3(4a +1)

7. $12n^5 + 16n^3$

here the smallest power of n is n^3 so, we can take n^3 common and both coefficients are divisible by 4 so taking 4n^3 common

$4n^3( 3n^2 + 4)$

9. $5k^2 - 40k+10$

Here we cannot take k common, as k is not a multiple of 10. For taking common it should be divisible by each value in the equation. But each value s divisible by 5 so, taking 5 common

$=5(k^2 - 8k + 2)$

11. $-60 + 60n^2 +50n^3$

Here we cannot take n common, as n is not a multiple of -60. For taking common it should be divisible by each value in the equation. But each value s divisible by 10 so, taking 10 common

$=10(-6 + 6n^2 +5n^3)$

13. $-36n^3 -12n-28$

Here we cannot take n common, as n is not a multiple of 28. For taking common it should be divisible by each value in the equation. But each value s divisible by -4 so, taking -4 common

$=-4(9n^3 + 3n +7)$

15. $63n^3+81n+18$

Here we cannot take n common, as n is not a multiple of 18. For taking common it should be divisible by each value in the equation. But each value s divisible by 9 so, taking 9 common

$=9(7n^3 + 9n + 2)$