The reaction given above is a combustion reaction. All combustion reactions are exothermic, meaning they give off heat when they react,
Answer:
6.Given,
Final Velocity =60m/s
Initial Velocity= 0
Time=10 sec
A=?
A=Final Velocity- Initial Velocity/time
=60-0/10
=60/10
=6m/s ans.
Explanation:
Acceleration = Final Velocity - Initial Velocity/Time
By using this Formula we can calculate Acceleration.
Answer:
#1: 0.00144 mmolHCl/mg Sample
#2: 0.00155 mmolHCl/mg Sample
#3: 0.00153 mmolHCl/mg Sample
Explanation:
A antiacid (weak base) will react with the HCl thus:
Antiacid + HCl → Water + Salt.
In the titration of antiacid, the strong acid (HCl) is added in excess, and you're titrating with NaOH moles of HCl that doesn't react.
Moles that react are the difference between mmoles of HCl - mmoles NaOH added (mmoles are Molarity×mL added). Thus:
Trial 1: 0.391M×14.00mL - 0.0962M×34.26mL = 2.178 mmoles HCl
Trial 2: 0.391M×14.00mL - 0.0962M×33.48mL = 2.253 mmoles HCl
Trial 3: 0.391M×14.00mL - 0.0962M×33.84mL = 2.219 mmoles HCl
The mass of tablet in mg in the 3 experiments is 1515mg, 1452mg and 1443mg.
Thus, mmoles HCl /mg OF SAMPLE<em> </em>for each trial is:
#1: 2.178mmol / 1515mg
#2: 2.253mmol / 1452mg
#3: 2.219mmol / 1443mg
<h3>#1: 0.00144 mmolHCl/mg Sample</h3><h3>#2: 0.00155 mmolHCl/mg Sample</h3><h3>#3: 0.00153 mmolHCl/mg Sample</h3>
Answer : The heat of reaction for the process is, 1374.7 kJ
Explanation :
According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.
The main chemical reaction is,

The intermediate balanced chemical reaction will be,
(1)

(2)

(3)

We reversing reaction 1, 3 and multiplying reaction 2 by 2 and then adding all the equations, we get :
(1)

(2)

(3)

The expression for heat of reaction for the process is:



Therefore, the heat of reaction for the process is, 1374.7 kJ