How much heat is required to melt 42.0 grams of water at 0*C? Hurry...
1 answer:
Answer:
Heat required to melt 42 g if ice is 13,860 J
Explanation:
The amount of heat required to melt grams of water at 0°C is given as follows;
The mass of the ice (water), m = 42 g
The latent heat of fusion of ice Δ= 330 J/g
Therefore, heat required to melt 42 grams is given as follows;
Heat required to melt ice = Mass of the ice, m × The specific latent heat of fusion of the ice, Δ
Heat required to melt 42 g if ice = m × Δ = 42 g × 330 J/g = 13,860 J
Heat required to melt 42 g if ice = 13,860 J.
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Answer: The pH at equivalence point for the given solution is 5.59.
Explanation:
At the equivalence point,
So, first we will calculate the moles of as follows.
= 0.0845 mol
Now, volume of present will be calculated as follows.
Volume =
=
= 0.1891 L
Therefore, the total volume will be the sum of the given volumes as follows.
110 ml + 189.1 ml
= 299.13 ml
or, = 0.2991 L
Now,
= 0.283 M
Chemical equation for this reaction is as follows.
As,
=
=
Now,
=
=
Now, pH will be calculated as follows.
pH =
=
= 5.59
Thus, we can conclude that pH at equivalence point for the given solution is 5.59.