The average atomic mass of the element is the sum of the products of the percentage abundance of isotope and its mass number. Therefore, for atomic mass equal to 58.933, the most abundant isotope is cobalt-59. Thus, the answer is letter C.
Explanation:
The two half equations are;
3e + HNO3 → NO
S→ H2SO4 + 6e
When balancing half equations, we have to make sure the number of electrons gained is equal to the number of electrons lost.
<em>Which factor will you use for the top equation?</em>
We multiply by 2 to make the number of electrons = 6e
<em>Which factor will you use for the bottom equation?</em>
We multiply by 1 to make the number of electrons = 6e
Answer:
Here you go! 50% of your writing piece
Explanation:
Foods produced from or using GM organisms are often referred to as GM foods.
GM foods are developed and marketed because there is some advantage either to the producer or consumer of these GM foods. GM seed developers wanted their products to be accepted by producers and have concentrated on innovations that bring direct benefit to farmers and generally the food industry.
One objective for developing plants based on GM organisms is to improve crop protection. The GM crops currently on the market are mainly aimed at an increased level of crop protection through the introduction of resistance against plant diseases caused by insects or viruses or through increased tolerance towards herbicides.
Resistance against insects is achieved by incorporating into the food plant the gene for toxin production from the bacterium Bacillus thuringiensis. GM crops that inherently produce this toxin have been shown to require lower quantities of insecticides in specific situations, where pest pressure is high.
I believe it would be a compound.
Answer: The volume of 0.684 mol of carbon dioxide at s.t.p. is 15.3 L
Explanation:
According to ideal gas equation:
P = pressure of gas = 1 atm (at STP)
V = Volume of gas = ?
n = number of moles = 0.684
R = gas constant = 
T =temperature =
(at STP)
Thus the volume of 0.684 mol of carbon dioxide at s.t.p. is 15.3 L
