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Semenov [28]
3 years ago
15

- m / 3 - 1 = 3 help please I'm stuck on this problem ​

Mathematics
1 answer:
Dafna1 [17]3 years ago
3 0

Answer:

Step-by-step explanation:

M = -12

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Which value of c makes the ratios equal? *
Nikitich [7]

Answer:

Option 4

The answer is 10.8

Step-by-step explanation:

5/6 = 9/c

5c = 9 × 6

5c = 54

5c/5 = 54/5

c = 10.8

Thus, The value of c is 10.8

<h3><u>For </u><u>Verification</u>;</h3>

5/6 = 9/c

5/6 = 9/10.8

0.833 = 0.833

Hence, L.H.S = R.H.S

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3 0
2 years ago
Solve the triangle.
vova2212 [387]

9514 1404 393

Answer:

  b = 71 m

  A = 83°

  C = 29°

Step-by-step explanation:

Many calculators can solve triangles. Apps are available for phone and tablet, or on the internet, like the one used here. In general, it takes less time to use one of these than to type your question into Brainly.

Given two sides and the angle between them, the Law of Cosines is the appropriate relation to use for finding the third side.

  b = √(a² +c² -2ac·cos(B))

  b = √(76² +37² -2·76·37·cos(67.75°)) ≈ √5015.48

  b ≈ 70.82005 ≈ 71 . . . meters

__

One a side and its opposite angle are known, the remaining angles are found using the Law of Sines.

  sin(A)/a = sin(B)/b

  A = arcsin(a·sin(B)/b) = arcsin(76·sin(67.75°)/70.82005) ≈ 83.33°

  A ≈ 83°

  C = arcsin(37·sin(67.75°)/70.82005) ≈ 28.92°

  C ≈ 29°

Or, you can find the remaining angle from 180° -68° -83°  = 29°.

3 0
2 years ago
I need help asap pls and thank you ;)
olga55 [171]

Answer:

\text{Length of AB is }\frac{ah}{a+h}

Step-by-step explanation:

Given △KMN, ABCD is a square where KN=a, MP⊥KN, MP=h.

we have to find the length of AB.

Let the side of square i.e AB is x units.

As ADCB is a square ⇒ ∠CDN=90°⇒∠CDP=90°

⇒ CP||MP||AB

In ΔMNP and ΔCND

∠NCD=∠NMP     (∵ corresponding angles)

∠NDC=∠NPM     (∵ corresponding angles)

By AA similarity rule,  ΔMNP~ΔCND

Also, ΔKAP~ΔKPM by similarity rule as above.

Hence, corresponding sides are in proportion

\frac{ND}{NP}=\frac{CD}{MP} \thinspace\thinspace and\thinspace\thinspace \frac{KA}{KP}=\frac{AB}{PM} \\\\\frac{ND}{NP}=\frac{x}{h} \thinspace\thinspace and\thinspace\thinspace \frac{KA}{KP}=\frac{x}{h}\\\\\frac{NP}{ND}=\frac{h}{x} \thinspace\thinspace and\thinspace\thinspace \frac{KP}{KA}=\frac{h}{x}\\\\\frac{PD}{ND}=\frac{h}{x}-1 \thinspace\thinspace and\thinspace\thinspace \frac{AP}{KA}=\frac{h}{x}-1\\

KA(\frac{h}{x}-1)=AP

ND(\frac{h}{x}-1)=PD

Adding above two, we get

(KA+ND)(\frac{h}{x}-1)=(AP+PD)

⇒ (KN-AD)=\frac{x}{(\frac{h}{x}-1)}

⇒ a-x=\frac{x}{(\frac{h}{x}-1)}

⇒ a-x=\frac{x^2}{h-x}

⇒ x^2=ah-ax-xh+x^2

⇒ x(h+a)=ah

⇒ x=\frac{ah}{a+h}

3 0
3 years ago
Need help in algebra quick
vlabodo [156]

Answer: 6 is the y intercept

Step-by-step explanation:

5 0
3 years ago
Sweets are sold loose, or pre-packed in 120g bags. The 120g bags are ?1.49 each. The loose sweets are ?0.89 for 100g. By calcula
tester [92]

Answer:

The loose sweets at ?0.89 for 100 g.


Step-by-step explanation:

First, calculate the price per gram. You do this by dividing the price by the grams.

?1.49 / 120 g =  1.49 / 120 = 0.0124 (4 dp)

Because the answer was very long, I have rounded it to 4 decimal places (4 dp).

?0.89 / 100 g = 0.89 / 100 = 0.0089

Next, you must calculate both pre-packed and loose sweets to the same weight. I am calculating them both to 100 g.

0.0124 x 100 = 1.24

0.0089 x 100 = 0.89

Finally, the cheapest product for 100 g will be the better value. In this case, it is the loose sweets.






6 0
3 years ago
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