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3 years ago

How to put 49% as a fraction in simplest form

Mathematics

2 answers:

Snezhnost [94]3 years ago

8 0

49/100 in simply that is your answer

liq [111]3 years ago

8 0

Well, % means "Out of 100," so it would be 49/100.
Now, you'd have to simplify, but in this case, you cannot.
<u><em>YOUR END PRODUCT IS 49/100!!</em></u>

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Evaluate the expression 3 + m if m = 4.

Drupady [299]

Answer:

Step-by-step explanation:

3 + m =

3 + 4 =

5 0

2 years ago

HELP ME PLEASE!!!!!!

Deffense [45]

9514 1404 393

Answer:

-2x +4

Step-by-step explanation:

We can write the polynomial p(x) in terms of the factors (x+2) and (x-3) as ...

p(x) = (x+2)(x-3)q(x) +ax +b

Where ax+b is the remainder from division by x^2 -x -6 = (x+2)(x-3). The values of 'a' and 'b' can be found from ...

p(-2) = 8 = -2a +b

p(3) = -2 = 3a +b

Subtracting the first equation from the second gives ...

(3a +b) -(-2a +b) = (-2) -(8)

5a = -10

a = -2

Then the first equation tells us ...

8 = -2(-2) +b

4 = b

So, the remainder from division by (x^2 -x -6) is (-2x +4).

5 0

2 years ago

I can't find the right answer

OlgaM077 [116]

Answer:

$x10$

Step-by-step explanation:

$x^2 > 100\\\\\mathrm{For\:}u^n\:>\:a\\\mathrm{,\:if\:}n\:\mathrm{is\:even}\mathrm{\:then\:}u\:\:\sqrt[n]{a}\\\\x\sqrt{100}\\\\\sqrt{100}=10\\\\x10$

7 0

3 years ago

The matrix A= (−3 0 1, 2 −4 2, −3 −2 1) has one real eigenvalue. Find this eigenvalue, its multiplicity, and the dimension of th

Aliun [14]

Answer:

a) -4

b) 1

c) 1

Step-by-step explanation:

a) The matrix A is given by:

$A=\left[\begin{array}{ccc}-3&0&1\\2&-4&2\\-3&-2&1\end{array}\right]$

to find the eigenvalues of the matrix you use the following:

$det(A-\lambda I)=0$

where lambda are the eigenvalues and I is the identity matrix. By replacing you obtain:

$A-\lambda I=\left[\begin{array}{ccc}-3-\lambda&0&1\\2&-4-\lambda&2\\-3&-2&1-\lambda\end{array}\right]$

and by taking the determinant:

$[(-3-\lambda)(-4-\lambda)(1-\lambda)+(0)(2)(-3)+(2)(-2)(1)]-[(1)(-4-\lambda)(-3)+(0)(2)(1-\lambda)+(2)(-2)(-3-\lambda)]=0\\\\-\lambda^3-6\lambda^2-12\lambda-16=0$

and the roots of this polynomial is:

$\lambda_1=-4\\\\\lambda_2=-1+i\sqrt{3}\\\\\lambda_3=-1-i\sqrt{3}$

hence, the real eigenvalue of the matrix A is -4.

b) The multiplicity of the eigenvalue is 1.

c) The dimension of the eigenspace is 1 (because the multiplicity determines the dimension of the eigenspace)

3 0

2 years ago

2 times 2 times 9 times 30045

Murrr4er [49]

1,081,620

2 x 2 is 4

9 x 30045 is 270,405

so 4 x 270,405 is 1,081,620

5 0

3 years ago