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GenaCL600 [577]
3 years ago
12

17. Find the value of each of these:(1) 4² (11) 92(iii) 100²(iv) 64²​

Mathematics
1 answer:
yaroslaw [1]3 years ago
6 0

Answer:

Step-by-step explanation:

4^{2}=4*4=16\\9^{2}= 9*9=81\\\\100^{2}=100*100=10000\\\\64^{2}=64*64=4096

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At the 6th grade school dance, there are 132 boys, 89 girls and 14 adults.
S_A_V [24]

Answer:

132:189 and

132 to 89

Step-by-step explanation:

I'm pretty sure

3 0
3 years ago
(x,-4) and (2,8): m = -3 find the missing value. it is in slope formula.
Snezhnost [94]

Answer:

The value of x = 6

Step-by-step explanation:

Given

  • The point (x,-4)
  • The point (2,8)

To determine

  • m = -3

Using the formula

Slope = m =  [y₂ - y₁] /  [x₂ - x₁]

here:

  • (x₁, y₁) = (x, -4)
  • (x₂, y₂) = (2, 8)
  • m = -3

so substitute (x₁, y₁) = (x, -4) , (x₂, y₂) = (2, 8)  and m = -3

m =  [y₂ - y₁] /  [x₂ - x₁]

-3 =  [8 - (-4)] / [2 - x]

-3 = [12] / [2-x]  

-3 (2-x) = 12

-6+3x = 12

3x = 12+6

3x = 18

divide  both sides by 3

3x/3 = 18/3

x = 6

Therefore, the value of x = 6

7 0
3 years ago
14a²b<br> 7a²b<br> =<br> Simplify
lidiya [134]

Step-by-step explanation:

if14a^2b/7a^2b answer is 2

and if the sign is addition then the answer is21a^2b if subtraction answer is7a^2b

4 0
3 years ago
HELP 30 POINTS!!!!!
Tamiku [17]

by pythagorean formula, the last side is √(61)

by cos rule

cos A

=  \frac{ {6}^{2}  + 61 -  {5}^{2} }{2 \times 6 \times  \sqrt{61} }  \\  =  \frac{72}{12 \sqrt{61} }   \\  =  \frac{6}{ \sqrt{61} }

A = 39.81

5 0
3 years ago
Complete the steps to solve the polynomial equation x3 – 21x = –20. According to the rational root theorem, which number is a po
jeka94

Answer:

Zeroes : 1, 4 and -5.

Potential roots: \pm 1, \pm 2, \pm 4, \pm 5, \pm 10, \pm 20.

Step-by-step explanation:

The given equation is

x^3-21x=-20

It can be written as

x^3+0x^2-21x+20=0

Splitting the middle terms, we get

x^3-x^2+x^2-x-20x+20=0

x^2(x-1)+x(x-1)-20(x-1)=0

(x-1)(x^2+x-20)=0

Splitting the middle terms, we get

(x-1)(x^2+5x-4x-20)=0

(x-1)(x(x+5)-4(x+5))=0

(x-1)(x+5)(x-4)=0

Using zero product property, we get

x-1=0\Rightarrow x=1

x-4=0\Rightarrow x=4

x+5=0\Rightarrow x=-5

Therefore, the zeroes of the equation are 1, 4 and -5.

According to rational root theorem, the potential root of the polynomial are

x=\dfrac{\text{Factor of constant}}{\text{Factor of leading coefficient}}

Constant = 20

Factors of constant ±1, ±2, ±4, ±5, ±10, ±20.

Leading coefficient= 1

Factors of leading coefficient ±1.

Therefore, the potential root of the polynomial are \pm 1, \pm 2, \pm 4, \pm 5, \pm 10, \pm 20.

3 0
4 years ago
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