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3 years ago

14

Proof triangles

1 answer:

Klio2033 [76]3 years ago

6 0

No, two sides the same is not enough.
You need more proof.

Side, angle, side. (SAS).
AD = DC
Angle ADB = Angle CDB
BD = BD

By the SAS property, the two triangles are the same.

I think this is one way to prove it...

Or, similarly...use ASA, (Angle, side, angle).

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Solve for x for 1 and 2

taurus [48]

Answer:

1. 37.5

2. 8

Step-by-step explanation:

1. the smaller triangle and the bigger triangle are similar, so the sides are also similar.

this means that 16/46 = 20/(x+20)

then, just solve that for x

16/46 = 20/(x+20)

divide both sides by 4

4/46 = 5/(x+20)

multiply both sides by (x + 20)

(x+20) * 4/46 = 5

multiply both sides by 46

4x + 80 = 230

subtract 80

4x = 150

divide 4

x = 37.5

2. do the same thing ( still similar triangles)

the equation would be (3x + 1)/10 = (7x - 1)/22

solve

22(3x + 1) = 10(7x - 1)

66x + 22 = 70x - 10

32 = 4x

x = 8

3 0

2 years ago

An elephant drinks 225 liters of water a day. How many liters in 2 days

Finger [1]

It is 450 liters in 2 days

4 0

3 years ago

Read 2 more answers

Two fifths of a number equals 564. what is the number

masya89 [10]

Answer:

1410

Step by step explanation:

<em>2</em><em>/</em><em>5</em><em>x</em><em>=</em><em>5</em><em>6</em><em>4</em>

<em>5</em><em>/</em><em>2</em><em>*</em><em>2</em><em>/</em><em>5</em><em>x</em><em>=</em><em>5</em><em>6</em><em>4</em><em>*</em><em>5</em><em>/</em><em>2</em>

<em>x</em><em>=</em><em>1</em><em>4</em><em>1</em><em>0</em>

<em>Proof</em><em>:</em><em> </em><em>2</em><em>/</em><em>5</em><em>*</em><em>1</em><em>4</em><em>1</em><em>0</em><em>=</em><em>5</em><em>6</em><em>4</em>

Hope it helps <3

5 0

3 years ago

Read 2 more answers

If 5 times a number is subtracted from 3 times its<br>square, the result is 2. Find the number.

grandymaker [24]

Answer:

x = 2 or x = - 1/3

Step-by-step explanation:

3x² - 5x = 2

3x² - 5x - 2 = 0

(x - 2) (3x + 1) = 0

x = 2 or x = - 1/3

5 0

3 years ago

PLs help 50 PTS!!!!! PLEASE ILL GIVE BRAINLIEST!!!!!

Nookie1986 [14]

Answer:

$\large\boxed{y=\dfrac{1}{4}x^2-x-4}$

Step-by-step explanation:

The equation of a parabola in vertex form:

$y=a(x-h)^2+k$

<em>(h, k)</em><em> - vertex</em>

The focus is

$\left(h,\ k+\dfrac{1}{4a}\right)$

We have the vertex (2, -5) and the focus (2, -4).

Calculate the value of <em>a</em> using $k+\dfrac{1}{4a}$

<em>k = -5</em>

$-5+\dfrac{1}{4a}=-4$ <em>add 5 to both sides</em>

$\dfrac{1}{4a}=1$ <em>multiply both sides by 4</em>

$4\!\!\!\!\diagup^1\cdot\dfrac{1}{4\!\!\!\!\diagup_1a}=4$

$\dfrac{1}{a}=4\to a=\dfrac{1}{4}$

Substitute

$a=\dfrac{1}{4},\ h=2,\ k=-5$

to the vertex form of an equation of a parabola:

$y=\dfrac{1}{4}(x-2)^2-5$

The standard form:

$y=ax^2+bx+c$

Convert using

$(a-b)^2=a^2-2ab+b^2$

$y=\dfrac{1}{4}(x^2-2(x)(2)+2^2)-5\\\\y=\dfrac{1}{4}(x^2-4x+4)-5$

<em>use the distributive property: a(b+c)=ab+ac</em>

$y=\left(\dfrac{1}{4}\right)(x^2)+\left(\dfrac{1}{4}\right)(-4x)+\left(\dfrac{1}{4}\right)(4)-5\\\\y=\dfrac{1}{4}x^2-x+1-5\\\\y=\dfrac{1}{4}x^2-x-4$

3 0

3 years ago