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Ber [7]
3 years ago
7

Draw a number line to show that 2/3 and 6/10 are equivalent

Mathematics
1 answer:
slega [8]3 years ago
8 0
Well thing is cant draw a line and 6/10 and 2/3 isnt equialent
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Prove that (Root of Sec A - 1 / Root of Sec A + 1) + (Root of Sec A + 1 / Root of Sec A - 1) = 2 cosec A
iVinArrow [24]

Answer:

The answer is below

Step-by-step explanation:

We need to prove that:

(Root of Sec A - 1 / Root of Sec A + 1) + (Root of Sec A + 1 / Root of Sec A - 1) = 2 cosec A.

Firstly, 1 / cos A = sec A, 1 / sin A = cosec A and tanA = sinA / cosA.

Also, 1 + tan²A = sec²A; sec²A - 1 = tan²A

\frac{\sqrt{secA-1} }{\sqrt{secA+1} } +\frac{\sqrt{secA+1} }{\sqrt{secA-1} } =\frac{(\sqrt{secA-1)}(\sqrt{secA-1})+(\sqrt{secA+1)}(\sqrt{secA+1}) }{(\sqrt{secA+1})(\sqrt{secA-1}) } \\\\=\frac{secA-1+(secA+1)}{\sqrt{sec^2A-secA+secA-1} } \\\\=\frac{2secA}{\sqrt{sec^2A-1} } \\\\=\frac{2secA}{\sqrt{tan^2A} } \\\\=\frac{2secA}{tanA} \\\\=\frac{2*\frac{1}{cosA} }{\frac{sinA}{cosA} }\\\\= 2*\frac{1}{cosA}*\frac{cosA}{sinA}\\\\=2*\frac{1}{sinAA}\\\\=2cosecA

7 0
3 years ago
Find the value of each variable:
Leona [35]

Answer:

5√3 = b

5 = d

10√3 = a

15 = c

Step-by-step explanation:

Sin60° = opp/hyp

sin60° = b/10

10sin60° = b

5√3 = b

Cos60° = adj/hyp

Cos60° = d/10

10Cos60° = d

5 = d

Sin30° = opp/hyp

Sin30° = 5√3/a

a = 5√3/Sin30°

a = 10√3

Tan30° = opp/adj

Tan30° = 5√3/c

c = 5√3/tan30°

c = 15

3 0
3 years ago
What does it mean for a product of factors to be expressed using exponents
MrMuchimi
Example:

7x7x7x7x7x7x7x7x7x7x7x7=84
there are 12 sevens
u put the deleted number as the big number (7) and the number of repeated numbers as the smaller sized number which is called the exponent (12)



3 0
3 years ago
Sketch the graphs <br><br> -2x +3y=-1
noname [10]

Answer:

Step-by-step explanation:

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8 0
2 years ago
To the relation a function Justify your answer
ahrayia [7]

Answer:

<em>No, because two points with the same y value have different values.</em>

<h3><u>PLEASE</u><u> MARK</u><u> ME</u><u> BRAINLIEST</u></h3>
7 0
3 years ago
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