9514 1404 393
Answer:
4) 6x
5) 2x +3
Step-by-step explanation:
We can work both these problems at once by finding an applicable rule.

where O(h²) is the series of terms involving h² and higher powers. When divided by h, each term has h as a multiplier, so the series sums to zero when h approaches zero. Of course, if n < 2, there are no O(h²) terms in the expansion, so that can be ignored.
This can be referred to as the <em>power rule</em>.
Note that for the quadratic f(x) = ax^2 +bx +c, the limit of the sum is the sum of the limits, so this applies to the terms individually:
lim[h→0](f(x+h)-f(x))/h = 2ax +b
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4. The gradient of 3x^2 is 3(2)x^(2-1) = 6x.
5. The gradient of x^2 +3x +1 is 2x +3.
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If you need to "show work" for these problems individually, use the appropriate values for 'a' and 'n' in the above derivation of the power rule.
Ist amount paid = $1500
Making $350 for 10 months = 10*350 = $3500
Total amount paid = 1500 + 3500 = 5000
So an amount of $5000 was paid to cover the cost of $4500 within the ten month period.
I = PRT
Interest, I = 5000 - 4500 = 500Time, t = 10 months = 10/12 = (5/6) year.Principal P = 4500
R = I /(PT) R = 500 / (4500*5/6)
R = (500*6) / (4500*5)
R = 0.1333..
R ≈ 13.33 % per annum.
ANSWER:
It is true as the divisibility rule of three says -
WE HAVE TO ADD ALL THE DIGITS OF THE NUMBER AND IF THAT SUM IS DIVISIBLE BY THREE THEN THE PARTICULAR NUMBER IS DIVISIBLE BY THREE.
EXAMPLE 2+7=9 and 3*3=9
HOPE IT HELPS!!!!
PLEASE MARK BRAINLIEST!!!!
Answer: 70
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