Can you elaborate more on the question?
Answer:
9 units.
Step-by-step explanation:
Let us assume that length of smaller side is x.
We have been given that the sides of a quadrilateral are 3, 4, 5, and 6. We are asked to find the length of the shortest side of a similar quadrilateral whose area is 9 times as great.
We know that sides of similar figures are proportional. When the proportion of similar sides of two similar figures is 
, then the proportion of their area is 
.
We can see that length of smaller side of 1st quadrilateral is 3 units, so we can set a proportion as:
Take positive square root as length cannot be negative:
Therefore, the length of the shortest side of the similar quadrilateral would be 9 units.
Ah, the commutative property.
a + b = b + a
xy = yx
When using the commutative property - a good way to remember it is to think of a community, in which each community member helps one another to a mutual outcome.
Using the commutative property we can rearrange this equation into a more sensical format:
-8.9 + 6.7 - 1.1
6.7 - 1.1 - 8.9
6.7 - 1.1 = 5.6
5.6 - 8.9 = -3.3
I hope this helps you
m (ACD)=m (ABD)
4x+4=6x-14
2x=18
x=9
m (ACD)=4x+4 =4.9+4=40
Answer:
Step-by-step explanation:
Hello!
The study variable is:
X: number of passengers that rest or sleep during a flight.
The sample taken is n=9 passengers and the probability of success, that is finding a passenger that either rested or sept during the flight, is p=0.80.
I'll use the binomial tables to calculate each probability, these tables give the values of accumulated probability: P(X≤x)
a. P(6)= P(X=6)
To reach the value of selecting exactly 6 passengers you have to look for the probability accumulated until 6 and subtract the probability accumulated until the previous integer:
P(X=6)= P(X≤6)-P(X≤5)= 0.2618-0.0856= 0.1762
b. P(9)= P(X=9)
To know the probability of selecting exactly 9 passengers that either rested or slept you have to do the following:
P(X≤9) - P(X≤8)= 1 - 0.8657= 0.1343
c. P(X≥6)
To know what percentage of the probability distribution is above six, you have to subtract from the total probability -1- the cumulated probability until 6 but without including it:
P(X≥6)= 1 - P(X<6)= 1 - P(X≤5)= 1 - 0.0856= 0.9144
I hope it helps!
