3/4log7(625)+2log7(x)=2 solve for x
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Annually The amount after 10 years = $ 7247.295
quarterly compound after 10 years = $7393.5
Continuously interest =$7,419
Given:
P = the principal amount
r = rate of interest
t = time in years
n = number of times the amount is compounding.
Principal = $4500
time= 10 year
Rate = 5%
To find: The amount after 10 years.
The principal amount is, P = $4500
The rate of interest is, r = 5% =5/100 = 0.05.
The time in years is, t = 10.
Using the quarterly compound interest formula:
A = P (1 + r / 4)4 t
A= 4500(1+.05/4)40
A= 4500(4.05/4)40
A= 4500(1.643)
Answer: The amount after 10 years = $7393.5
Using the Annually compound interest formula:
A = P (1 + r / 100) t
A= 4500(1+5/100)10
A= 4500(105/100)10
Answer: The amount after 10 years = $ 7247.295
Using the Continuously compound interest formula:
e stands for Napier’s number, which is approximately 2.7183
A= $2,919
Answer: The amount after 10 years = $4500+$2,919=$7,419
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Answer:
Step-by-step explanation:
It is given that the distance of the nearest exit door is no more than the 200 feet. so this can be represented using an inequality.
since it is no more than 200 means the maximum it can be is 200 feet .
Now we are representing the distance using the variable d and we have established that the maximum value of d can be 200 so it can represented
by this inequality