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2 years ago

8

The length of a rectangle is 5 feet and the width is x the perimeter is less than 15 feet write and solve an inequality to find

the value of x
please help me with this and ill give you a brainlist

2 answers:

topjm [15]2 years ago

7 0

Answer:

5 ft * x ft

x ≤ 3 ft

Step-by-step explanation:

mote1985 [20]2 years ago

4 0

The answer is X equals 3

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Is 2.6 bigger than 2.661

Sauron [17]

2.6 = 2.600
So, 2.6 is not bigger than 2.661

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3 years ago

Read 2 more answers

Use the information provided to determine a 95% confidence interval for the population variance. A researcher was interested in

Leno4ka [110]

Answer:

The 95% confidence interval for the population variance is (8.80, 32.45).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the population variance is given as follows:

$\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}$

It is provided that:

<em>n</em> = 20

<em>s</em> = 3.9

Confidence level = 95%

⇒ <em>α</em> = 0.05

Compute the critical values of Chi-square:

$\chi^{2}_{\alpha/2, (n-1)}=\chi^{2}_{0.05/2, (20-1)}=\chi^{2}_{0.025,19}=32.852\\\\\chi^{2}_{1-\alpha/2, (n-1)}=\chi^{2}_{1-0.05/2, (20-1)}=\chi^{2}_{0.975,19}=8.907$

*Use a Chi-square table.

Compute the 95% confidence interval for the population variance as follows:

$\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}$

$\frac{(20-1)\cdot (3.9)^{2}}{32.852}\leq \sigma^{2}\leq \frac{(20-1)\cdot (3.9)^{2}}{8.907}\\\\8.7967\leq \sigma^{2}\leq 32.4453\\\\8.80\leq \sigma^{2}\leq 32.45$

Thus, the 95% confidence interval for the population variance is (8.80, 32.45).

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3 years ago

Kelli and her family went to the beach for a vacation. They drove 293 miles in 7 hours to get there. ABOUT how many miles did th

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Answer:

41.86 miles each hour

Step-by-step explanation:

Kelli and her family went to the beach for a vacation. They drove 293 miles in 7 hours to get there. ABOUT how many miles did they drive each hour?

This Question is calculated as:

7 hours = 293 miles

1 hour = x miles

Cross Multiply

7 hours × x = 1 × 293 miles

x = 293 miles/7 hours

x = 41.857142857 miles per hour

x ≈ 41.86 miles per hour

Hence, they drove 41.86 miles each hour

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Answer:

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Step-by-step explanation:

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