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Llana [10]
3 years ago
6

In the diagram, how many angles must be supplementary with angle 14?

Mathematics
2 answers:
Andreas93 [3]3 years ago
6 0

Answer:

2

Step-by-step explanation:

angles 13 and 15 are supplementary with 14

since none of the lines are parallel

notka56 [123]3 years ago
4 0

Answer: There are two angles.

Step-by-step explanation:

Since we have shown in the figure:

\angle 14+\angle 15=180^\circ  ( ∵ Linear pair)

Similarly,

\angle 13+\angle 14=180^\circ  ( ∵ Linear pair)

So, we can see that

there are two angles that must be supplementary with angle 14.

Hence, there are two angles.

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Exercise 7.3.5 The following is a Markov (migration) matrix for three locations        1 5 1 5 2 5 2 5 2 5 1 5 2 5 2 5 2
fredd [130]

Answer:

Both get the same results that is,

\left[\begin{array}{ccc}140\\160\\200\end{array}\right]

Step-by-step explanation:

Given :

\bf M=\left[\begin{array}{ccc}\frac{1}{5}&\frac{1}{5}&\frac{2}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{1}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{2}{5}\end{array}\right]

and initial population,

\bf P=\left[\begin{array}{ccc}130\\300\\70\end{array}\right]

a) - After two times, we will find in each position.

P_2=[P].[M]^2=[P].[M].[M]

M^2=\left[\begin{array}{ccc}\frac{1}{5}&\frac{1}{5}&\frac{2}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{1}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{2}{5}\end{array}\right]\times \left[\begin{array}{ccc}\frac{1}{5}&\frac{1}{5}&\frac{2}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{1}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{2}{5}\end{array}\right]

     =\frac{1}{25} \left[\begin{array}{ccc}7&7&7\\8&8&8\\10&10&10\end{array}\right]

\therefore\;\;\;\;\;\;\;\;\;\;\;P_2=\left[\begin{array}{ccc}7&7&7\\8&8&8\\10&10&10\end{array}\right] \times\left[\begin{array}{ccc}130\\300\\70\end{array}\right] = \left[\begin{array}{ccc}140\\160\\200\end{array}\right]

b) - With in migration process, 500 people are numbered. There will be after a long time,

After\;inifinite\;period=[M]^n.[P]

Then,\;we\;get\;the\;same\;result\;if\;we\;measure [M]^n=\frac{1}{25} \left[\begin{array}{ccc}7&7&7\\8&8&8\\10&10&10\end{array}\right]

                                   =\left[\begin{array}{ccc}140\\160\\200\end{array}\right]

4 0
3 years ago
The first two diamonds are filled in, can you figure out how the numbers are related when
balu736 [363]

Answer:

Step-by-step explanation:

Upper box in the diamond: Add the two numbers  ⇒ (-2) + 3 = -1

Bottom box in the diamond : Multiply the two numbers ⇒ (-2) * 3 = -6

3) Upper box = (-6) +  (-3)  = (-9)

Bottom box = (-6) *(-3) = 18

4) Upper box  = 1 +(-11) = -10

 Bottom box = 1 *(-11) = -11

5) Upper box = 7+8 = 15

Bottom box = 7*8 = 56

7 0
2 years ago
Write an equation in slope-intercept form of<br> the line that passes through (-6,4) and<br> (-1,2).
xz_007 [3.2K]

Answer:

Step-by-step explanation:

(-6 , 4)  & (-1 , 2)

Slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

         = \frac{2-4}{-1-[-6]}\\\\= \frac{-2}{-1+6}\\\\= \frac{-2}{5}

m = -2/5   & (-6 , 4)

y -y1 = m(x -x1)

y - 4 = \frac{-2}{5}(x - [-6])\\\\y - 4 = \frac{-2}{5}(x + 6)\\\\y - 4 = \frac{-2}{5}x + 6*\frac{-2}{5}\\\\y = \frac{-2}{5}x -\frac{12}{5}+4\\\\y=\frac{-2}{5}x-\frac{12}{5}+\frac{4*5}{1*5}\\\\y=\frac{-2}{5}x-\frac{12}{5}+\frac{20}{5}\\\\y=\frac{-2}{5}x+\frac{8}{5}

6 0
3 years ago
How much water do you add...
Alecsey [184]

Answer: 36.67 grams of water is added.

Step-by-step explanation:

Let the amount of water is added be 'x'.

Amount of sugar = 5 g

We need to make 12% of sugar syrup.

x grams of water is added to 5 g of sugar, to 12% of sugar syrup.

so, it becomes,

\frac{5}{5+x}=\frac{12}{100}\\\\100\times 5=12(5+x)\\\\500=60+12x\\\\500-60=12x\\\\440=12x\\\\\frac{440}{12}=x\\\\36.67\ g=x

Hence, 36.67 grams of water is added.

7 0
3 years ago
Help idk how to do this ASAP please
Sergio039 [100]

Answer:

The area of ∆DEF = 4.5in²

Step-by-step explanation:

From the above diagram,

∆BAC ~∆DEF

It is important to note that if two triangles are similar, the ratio of their areas is equal or equivalent to the ratio of the areas of their sides

This means for the above question, that

We have the bigger triangle = ∆BAC has a side of 4 in and Area = 8 in²

The small triangle has a side of 3in

Finding the scale factor k = ratio of the sides of both Triangles

k = 4/3

k² = (4/3)²

k² = 16/9

Hence,

Area of ∆BAC/ Area of ∆DEF = 16/9

8in²/Area of ∆DEF = 16/9

We cross Multiply

8 in² × 9 = Area of ∆DEF × 16

Divide both sides by 16

Area of ∆DEF = 72/16

= 4.5in²

Therefore, the Area of ∆DEF rounded to the nearest tenth = 4.5in²

8 0
3 years ago
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