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3 years ago

In the diagram, how many angles must be supplementary with angle 14?

Mathematics

2 answers:

Andreas93 [3]3 years ago

6 0

Answer:

Step-by-step explanation:

angles 13 and 15 are supplementary with 14

since none of the lines are parallel

notka56 [123]3 years ago

4 0

Answer: There are two angles.

Step-by-step explanation:

Since we have shown in the figure:

$\angle 14+\angle 15=180^\circ$ ( ∵ Linear pair)

Similarly,

$\angle 13+\angle 14=180^\circ$ ( ∵ Linear pair)

So, we can see that

there are two angles that must be supplementary with angle 14.

Hence, there are two angles.

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Black_prince [1.1K]

Answer:

D. (4,3)

Step-by-step explanation:

I calculated it logically

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3 years ago

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Does the point (-4, 2) lie inside or outside or on the circle x^2 + y^2 = 25?

stiv31 [10]

Given equation of the Circle is ,

$\sf\implies x^2 + y^2 = 25$

And we need to tell that whether the point (-4,2) lies inside or outside the circle. On converting the equation into Standard form and determinimg the centre of the circle as ,

$\sf\implies (x-0)^2 +( y-0)^2 = 5 ^2$

Here we can say that ,

• Radius = 5 units

• Centre = (0,0)

Finding distance between the two points :-

$\sf\implies Distance = \sqrt{ (0+4)^2+(2-0)^2} \\\\\sf\implies Distance = \sqrt{ 16 + 4 } \\\\\sf\implies Distance =\sqrt{20}\\\\\sf\implies\red{ Distance = 4.47 }$

Here we can see that the distance of point from centre is less than the radius.

Hence the point lies within the circle .

5 0

3 years ago

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Louis built a swimming pool. The depth of the swimming pool is 5 feet. What is the volume of water that it will take to fill the

julia-pushkina [17]

Answer:

For a rectangular prism-like swimming pool: $V = w\cdot l \cdot h$ . $V = 360\,ft^{3}$ when $h = 5\,ft$ , $l = 12\,ft$ and $w = 6\,ft$ .

Step-by-step explanation:

Let assume that swimming pool has a rectangular base and depth is the same at any point at the bottom. In addition, let $w$ and $l$ be the width and length of the swimming pool. Then, the volume needed to fill the swimming pool is: