A polynomial function that has roots 1 and 3 + i. The complex conjugates theorem states that must also be a (blank) root.
2 answers:
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Answer:
vertex = (2, - 9 )
Step-by-step explanation:
Given a quadratic in standard form : ax² + bx + c : a ≠ 0
Then the x- coordinate of the vertex is
= -
x² - 4x - 5 ← is in standard form
with a = 1, b = - 4, thus
= -
= 2
Substitute this value into the quadratic for corresponding value of y
(2)² - 4(2) - 5 = 4 - 8 - 5 = - 9
vertex = (2, - 9 )