A polynomial function that has roots 1 and 3 + i. The complex conjugates theorem states that must also be a (blank) root.

Mathematics

2 answers:

m_a_m_a [10]3 years ago

6 0

Complex roots come in pairs

if you have a root of 3+i you must have a root of 3-i

Alenkasestr [34]3 years ago

3 0

Answer:

in Edge: Second question: The factors of the polynomial are (X-1)[X-(3+i)] [X-(3-i)]

in Edge: Third question: The polynomial function of least degree with a leading coefficient of 1 is: A= -7 B= 16 C= -10

Step-by-step explanation:

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alex41 [277]

Answer:

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Step-by-step explanation:

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3 years ago

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What is the value of x for part A and part B

GuDViN [60]

Part A :

So the two sides are equivalent,

$9x - 18 = 3x$

Solve for x and get 3.

~~

Answer : x = 3

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Part B :

To find JM, simply substitute x for 3 and solve,

$9(3) - 18$
$27 - 18 = 9$
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Answer : JM = 9

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I hope that helps you out!!

Any more questions, please feel free to ask me and I will gladly help you out!!

~Zoey

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3 years ago

0.3/10 as a decimal plz help

muminat

Answer:

0.30

Step-by-step explanation:

The 0 goes in the tenths place because it was 0.3/10 I hope this helps at all:)

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3 years ago

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