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igor_vitrenko [27]
3 years ago
6

If the outliers are not included, what is the mean of the data set?

Mathematics
2 answers:
ioda3 years ago
4 0
If you don't include the outlier (50) then it is 79.7
enyata [817]3 years ago
4 0

If your data set includes the numbers 50 and 83 then the only outlier is 50, so when you add 76+79+79+80+81+82+82+83=642/8 total number of in data set=80.25 so the correct mean of the data set is 80.

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Solve for x please answer quick and please the right answer-2(x+1/4)+1=5
laila [671]
-2\left(x+\dfrac{1}{4}\right)+1=5\\
-2x-\dfrac{1}{2}=4\\
-2x=\dfrac{8}{2}+\dfrac{1}{2}\\
-2x=\dfrac{9}{2}\\
x=-\dfrac{9}{4}
8 0
4 years ago
6 divided by 7215 and i need help its to hard????
forsale [732]

Answer:

If you mean 6 / 7215 it is 0.00083

but if you meant 7215 / 6 it is 1202.5

Step-by-step explanation:

5 0
2 years ago
-x + 1/2 = x + 41/2<br> *PLEASE SHOW WORK*
ollegr [7]
  -x + 1/2 = x + 4 1/2
  +x           +x
         1/2 = 2x + 4 1/2
       -4 1/2       - 4 1/2
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6 0
3 years ago
Help please<br> This question is stressing me out
Delvig [45]

Answer:

Maximum: C= 6(5) + 2y or <u>C= 30 + 2y</u>

Step-by-step explanation:

X can be greater than or equal to 0, but can also be less than or equal to 5.

Y is greater than or equal to 0.

4 times x then subtracted by y is greater than or equal to 1.

Since X can't go higher than 5, the maximum is 5.

Y can be anything since it can be greater than or egual to 0 and either way it would be greater than one.

I hope I could help!

7 0
3 years ago
Select the correct answer. which expression is equivalent to the given expression? assume the denominator does not equal zero. a
Alexxandr [17]

If the denominator does not equal 0, the equivalent expression of \frac{14x^4y^6}{7x^8y^2} is \frac{2y^{4}}{x^{4}}\frac{x^{10} y^{14}}{729}

<h3>How to determine the equivalent expression?</h3>

The expression is given as:

\frac{14x^4y^6}{7x^8y^2}

Divide 14 by 7

\frac{14x^4y^6}{7x^8y^2} = \frac{2x^4y^6}{x^8y^2}

Apply the law of indices

\frac{14x^4y^6}{7x^8y^2} = \frac{2y^{6-2}}{x^{8-4}}

Evaluate the differences in the exponents

\frac{14x^4y^6}{7x^8y^2} = \frac{2y^{4}}{x^{4}}

Hence, the equivalent expression of \frac{14x^4y^6}{7x^8y^2} is \frac{2y^{4}}{x^{4}}

Read more about equivalent expressions at:

brainly.com/question/2972832

#SPJ4

4 0
2 years ago
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