If you shift function f(x) a units right you'll get f(x-a) function.
So if you have f(x) = x², you'll get f(x-10) = (x-10)² - answer B
other formulas:
a units left: f(x+a)
a units up: f(x)+a
a units down: f(x)-a
Answer:
hola
Step-by-step explanation:
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![\sf{\qquad\qquad\huge\underline{{\sf Answer}}}](https://tex.z-dn.net/?f=%20%5Csf%7B%5Cqquad%5Cqquad%5Chuge%5Cunderline%7B%7B%5Csf%20Answer%7D%7D%7D%20)
The equation of circle in standard form can be represented as :
![\qquad \sf \dashrightarrow \:(x - h) {}^{2} + (y - k) {}^{2} = r {}^{2}](https://tex.z-dn.net/?f=%5Cqquad%20%5Csf%20%20%5Cdashrightarrow%20%5C%3A%28x%20-%20h%29%20%7B%7D%5E%7B2%7D%20%20%2B%20%28y%20-%20k%29%20%7B%7D%5E%7B2%7D%20%20%3D%20r%20%7B%7D%5E%7B2%7D%20)
where,
- h = x - coordinate of centre = 0
- k = y - coordinate of centre = 0
- r = radius of circle = 6 units
now, let's plug in the values :
![\qquad \sf \dashrightarrow \:(x - 0) {}^{2} + (y - 0) {}^{2} = 6 {}^{2}](https://tex.z-dn.net/?f=%5Cqquad%20%5Csf%20%20%5Cdashrightarrow%20%5C%3A%28x%20-%200%29%20%7B%7D%5E%7B2%7D%20%20%2B%20%28y%20-%200%29%20%7B%7D%5E%7B2%7D%20%20%3D%206%20%7B%7D%5E%7B2%7D%20)
![\qquad \sf \dashrightarrow \: {x}^{2} + {y}^{2} = 36](https://tex.z-dn.net/?f=%5Cqquad%20%5Csf%20%20%5Cdashrightarrow%20%5C%3A%20%7Bx%7D%5E%7B2%7D%20%20%2B%20%20%7By%7D%5E%7B2%7D%20%20%3D%2036)
That's the required equation of circle.
Answer:
sin25 = cos65
Step-by-step explanation: