any multiple of 12
Since 2, 3 and 4 divide exactly into the number of rocks
We are looking for the common multiples of 2, 3 and 4
2 × 3 × 4 = 24 is possible but dividing by 2 gives 12 the lowest common multiple
Any multiple of 12 gives a possible number of rocks.
Answer:
C)16
Step-by-step explanation:
assuming the rhombus is named ABCD and E is where the diagonals meet.
Rhombus is a quadrilateral in which
- All sides are equal
- Opposite internal angles are equal
- Diagonals bisect each other at right angles
As rhombus is ABCD , AC is a diagonal which is bisected by E (According to the properties of Rhombus)
therefore AC will be twice of AE which is given to be 8
⇒ Answer is 16
