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il63 [147K]
3 years ago
5

Describe the graph of the equation y=0. is the equation a function

Mathematics
2 answers:
miv72 [106K]3 years ago
5 0

Answer:

The function is defined along the x-axis. Yes the equations y = 0 is a function

Step-by-step explanation:

It means that  y  is  0  in all values of  x

creativ13 [48]3 years ago
4 0

The graph y = 0 would be a horizontal line that overlaps the x-axis. This would be a function because the y-value (zero) never has the same x-value.  This means that it would pass the vertical line test since the graph would only pass through it once.

Hope this helped!

~Just a girl in love with Shawn Mendes

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Find the value of x:<br> I WILL AWARD BRAINLIEST, ANSWER QUICK PLEASE
Murrr4er [49]

Answer:

draw line through X which is parallel to other two lines

by alternative angles, X = 50 + 70 = 120°

6 0
2 years ago
Fractions : $1,000 <br><br> 1/4. <br><br> Someone plz help
olga2289 [7]

Not 100% sure exactly what you’re asking, but if you are asking what is 1/4 of $1,000, all we need to do to find the answer is <u>divide</u> $1,000 by the <u>denominator</u> of the fraction which is <u>4</u>

$1,000 ÷ 4 = $250

Therefore, 1/4 of $1,000 is $250


Hope this helps you

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8 0
3 years ago
Select the statements that are true based on the following given information. D = {x | x is a whole number} E = {x | x is a perf
likoan [24]
<h3>2 Answers: Choice C and Choice D</h3>

==========================================================

Explanation:

Let's write the roster notation of each set

D = {0, 1, 2, 3, ...} the dots indicate the pattern goes on forever

E = {0, 1, 4, 9, 16, 25} = list of perfect squares smaller than 36

F = {20, 22, 24, 26, 28, 30} = even numbers between 20 and 30

----------------

If we intersect sets D and E, we're looking for what numbers are in both sets at the same time. Therefore, D ∩ E = {0, 1, 4, 9, 16, 25} which is the exact same as set E. This is because all of set E is inside of set D. We say that set E is a subset of set D. So, D ∩ E = E.

Choice A is very close to being true. The problem is that 25 is missing from the set {1,4,9,16}. So this is why choice A is false.

----------------

Now let's intersect sets D and F. The numbers they have in common are {20, 22, 24, 26, 28, 30} which is exactly what set F is. So set F is a subset of set D. We can write D ∩ F = F in much the same way we can say D ∩ E = E.

D ∩ F = {12,14,16,18} is not true. A number like 12 is not between 20 and 30, so it cannot be in set F.

Choice B is false so we cross it off the list.

----------------

Choice C is true and here's why

D ∪ (E ∩ F) is the same as saying D ∪ G where G is the set of intersecting E and F together. In other words, G = E ∩ F

We don't really need to even worry about sets E, F or G. All that matters here is set D.

When we write D ∪ (E ∩ F) or D ∪ G, we're saying "a number is in set D, or it is in set G". If it is in D, then it's a whole number. Otherwise, it's in a subset of whole numbers.

Overall, D ∪ G and D ∪ (E ∩ F) form the entire set of whole numbers.

------------------

Choice D is true.

E and F have nothing in common

E = {0, 1, 4, 9, 16, 25}

F = {20, 22, 24, 26, 28, 30}

So intersecting them leads to the empty set. This is the set with nothing inside it, not even 0.

------------------

Choice F is false

These two sets below

E = {0, 1, 4, 9, 16, 25}

F = {20, 22, 24, 26, 28, 30}

union together to get

H = {0,1,4,9,16,20,22,24,25,26,28,30}

just toss all of the numbers together into one big set

Notice how each of these numbers are whole numbers, so they are part of set D. This means set H is also a subset of set D.

When we intersect sets D and H, we end up with set H. We do not simply end up with the set with 25 only inside it.

6 0
3 years ago
Please Help Me!
melisa1 [442]

Answer: B or 52

Step-by-step explanation: I will explain later

6 0
2 years ago
1/2 (2n + 6) <br> simply the answer and show work
Evgesh-ka [11]

Answer:

The answer is n + 3.

Step-by-step explanation:

1) Simplify.

\frac{2n + 6}{2}

2) Factor out the common term 2.

\frac{2( n+ 3)}{2}

3) Cancle 2.

n + 3

<u>Th</u><u>e</u><u>refor</u><u>,</u><u> </u><u>the</u><u> </u><u>answer</u><u> </u><u>is</u><u> </u><u>n</u><u> </u><u>+</u><u> </u><u>3</u><u>.</u>

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2 years ago
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