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kogti [31]
3 years ago
10

Brainiest to the correct person 983 times 4876

Mathematics
2 answers:
steposvetlana [31]3 years ago
3 0

Answer:4793108

Step-by-step explanation:

aivan3 [116]3 years ago
3 0

4793108

Is the correct awnser

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What is the length of AB?<br> A(2,-6). BIZ, 1)
Arada [10]

Answer:

The length of AB is \sqrt{74}\ units

Step-by-step explanation:

we know that

The formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

A(2,-6)\\B(7,1)  

substitute

d=\sqrt{(1+6)^{2}+(7-2)^{2}}

d=\sqrt{(7)^{2}+(5)^{2}}

d=\sqrt{49+25}

AB=\sqrt{74}\ units

4 0
4 years ago
You are given that a wheel has a radius of 2 feet and a spin rate of 10 revolutions per minute. Describe how you would determine
ss7ja [257]

Answer:

About 126 ft/min

Step-by-step explanation:

We know r = 2 feet, and that the wheel has an angular speed of 10 rpms, or 10 revolutions per minute. Our goal is to get the speed in ft/sec.

10 rev            1 minute             2π radians            2 feet

-----------  ×    ----------------   ×    ------------------    ×   ------------

1 minute       60 seconds         1 revolution           1 radian

= 10 * 2π * 2 = 126 ft/minute

The answer is reasonable. Another, simple approach to this would be using the formula 2π * r * rpm. If so, 2π * 2 * 10 which would be 126 ft/minute.

6 0
3 years ago
I need to know what 1/5(6+3+1). And whatever is in the parentheses is to the second power
Inga [223]

Answer:

20

Step-by-step explanation:

1/5(6+3+1)^2

PEMDAS says parentheses first

1/5(10)^2

Then exponents

1/5 *100

Then multiply

20

8 0
3 years ago
Read 2 more answers
Determine the domain and range of (g ○ f)(x) if f of x is equal to 4 over the quantity x squared minus 4 end quantity and g(x) =
lara [203]

The domain and range of a function are the possible <em>x and y values </em>of the function.

<em>The domain and the range of the function is: (a) </em>\mathbf{D:\{x \in R|x \ne -2,2\}}<em> and </em>\mathbf{R:\{(-\infty,1) \cup (2,\infty)\}}<em />

The functions are given as:

\mathbf{f(x) = \frac{4}{x^2 - 4}}

\mathbf{g(x) = x + 2}

(g o f)(x) is calculated as:

\mathbf{(g\ o\ f)(x) = g(f(x))}

So, we have:

\mathbf{(g\ o\ f)(x) = \frac{4}{x^2 - 4} + 2}

Take LCM

\mathbf{(g\ o\ f)(x) = \frac{4 + 2x^2 - 8}{x^2 - 4} }

\mathbf{(g\ o\ f)(x) = \frac{2x^2 - 4}{x^2 - 4} }

Represent the denominator as follows, to calculate the domain

\mathbf{x^2 - 4 \ne 0 }

Add 4 to both sides

\mathbf{x^2 \ne 4 }

Take square roots of bot sides

\mathbf{x \ne \±2 }

Hence, the domain of the function is:

\mathbf{D:\{x \in R|x \ne -2,2\}}

On the graph of \mathbf{(g\ o\ f)(x) = \frac{2x^2 - 4}{x^2 - 4} } (see attachment), the function does not have a value from <em>y = 1 to 2.</em>

Hence, the range is:

\mathbf{R:\{(-\infty,1) \cup (2,\infty)\}}

Read more about domain and range at:

brainly.com/question/1632425

5 0
2 years ago
Read 2 more answers
Rita made $289 for 17 hours of work. At the same rate, how much would she make for 13 hours of work?​
11111nata11111 [884]

Answer:$221

Step-by-step explanation:

Divide 289 by 17

Get 17, then multiply by 13.

6 0
3 years ago
Read 2 more answers
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