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Sergio [31]
3 years ago
12

Name the algebraic property demonstrated in the example below: If x = 3 and 3 = y, then x = y.

Mathematics
2 answers:
Ivan3 years ago
7 0
Transitive property of equality

Two quantities that are equal to the same thing are equal to each other

:) Hope this helps
rjkz [21]3 years ago
4 0
If x = 3 and 3 = y, then x = y

This is an example of the transitive property of algebra. Transitive property is one of the properties of equality.

Other properties of equality in algebra are:
1) multiplicative property of zero: a * 0 =  0 = 0 * a
2) zero product : if ab = 0 ; then a = 0 or b = 0
3) reflexive : a = a
4) symmetric : if a = b, then b = a
5) addition : if a = b , then a + c = b + c
6) subtraction : if a = b , then a - c = b - c
7) multiplication: if a = b , then ac = bc
8) division: if a = b and c not = 0, then a / c = b / c
9) Substitution : if a = b, then b can substitute for a in any equation.




You might be interested in
Write a number with one decimal place,that is bigger than 6 4/5 but smaller than 7 how can I solve this
statuscvo [17]
Hello!

The easiest way to solve this would be to convert 6 4/5 to a decimal. We know that to convert a fraction to a decimal, we must divide the numerator by the denominator. 

4 / 5 = 0.8 

0.8 + 6 = 6.8

So, 6 4/5 is 6.8 as a decimal. 

See how it's easier now that we've converted the mixed number to a decimal? 

There could be many numbers between 6.8 and 7. Some examples are: 

6.81, 6.82, 6.83, 6.9, etc. 




7 0
4 years ago
HHHHHHHHHHHHHEEEEEEEEEEEEEEEEEEELLLLLLLLLLLLLLLLLLPP
Naya [18.7K]

Answer:

the 1st answer is H, yw

Step-by-step explanation:

quadrant I is on the top right, quadrant II is on the upper left, quadrant III is on the bottom left, and quadrant IV is on the bottom right. H is located in the top left (quadrant 2)

7 0
3 years ago
Suppose that an automobile manufacturer designed a radically new lightweight engine and wants to recommend the grade of gasoline
yawa3891 [41]

Answer:

B) 4.07

Step-by-step explanation:

First we need to calculate the mean of all the data, which is the same as the mean of the means of each grade of gasoline:

Regular    BelowRegular   Premium   SuperPremium

39.31             36.69                38.99             40.04

39.87            40.00                40.02             39.89

39.87            41.01                  39.99             39.93

X1⁻=39.68    X2⁻= 39.23       X3⁻= 39.66    X4⁻=  39.95

Xgrand⁻ = (39.68+39.23+39.66+39.95)/4 = 39.63

Next we need to calculate the sum of squares within the group (SSW) and the sum of squares between the groups (SSB), and the respective degrees of freedom):

SSW = [ (39.31-39.68)² + (39.87-39.68)² + (39.87-39.68)² ] + [ (36.69-39.23)² + (40.00-39.23)² + (41.01-39.23)² ] + [ (38.99-39.66)² + (40.02-39.66)² + (39.99-39.66)² ] + [ (40.04-39.95)² + (39.89-39.95)² + (39.93-39.95)² ] = [0.2091] + [10.2129] + [0.6874] + [0.0121] = 11.12

SSW =  11.12

Degrees of freedom in this case is calculated by m(n-1), with m being the number of grades of gasoline (4) and n being the number of trial results for each one (3), so we would have 4(3-1) = 8 degrees of freedom

SSB = [ (39.68-39.63)² + (39.68-39.63)² + (39.68-39.63)²] + [ (39.23-39.63)² + (39.23-39.63)² + (39.23-39.63)² ] + [ (39.66-39.63)² + (39.66-39.63)² + (39.66-39.63)² ] + [ (39.95-39.63)² + (39.95-39.63)² +(39.95-39.63)² ] = [0.0075] + [0.48] + [0.0027] + [0.3072] = 0.7974

SSB =  0.80

For this case, the degrees of freedom are m-1, so we would have 4-1 = 3 degrees of freedom

Now we can establish the hypothesis for the test:

H0: μ1 = μ2 = μ3 = μ4

The null hypothesis states that the means of miles per gallon for each fuel are the same, indicating that the drade of gasoline does not make a difference, therefore our alternative hypothesis will be:

H1: the grade of gasoline does makes a difference

We will use the F statistic to test the hypothesis, which is calculated like follows:

F - statistic = (SSB/m-1) / (SSW/m(n-1)) = (0.80/3) / (11.12/8) = 0.19

We know that the level of significance we are using is α = 0.05, so to find the critical value F we need to look at some table of critical values for the F distribution for the 0.05 significance level (like the attached image). Then we just need to look fot the value that is located in the intersection between the degrees of freedom we have in the numerator (horizontal) and the denominator (vertical) of the statistic (3 and 8). That critical value is:

Fc = 4.07

3 0
3 years ago
The HCP prescribes methotrexate 7.5 mg PO weekly, in 3 divides doses for a child with rheumatoid arthritis whose body surface ar
dexar [7]

Answer:

1.5mg

Step-by-step explanation:

From the question, we are told that the HCP prescribed 7.5 mg of PO weekly

The therapeutic dosage is given in the question as 5 - 15 mg/m² weekly.

The child's body surface area is given = 0.6m²

The mg of PO that the nurse should administer in each of the three doses given weekly is calculated as

7.5mg/ 5mg/m²

= 1.5 mg of PO

4 0
3 years ago
PLEASEEEE 100 POINTS AND BRAINLIEST PLEASEE HELPP ASAPPPPPPPPP!!!!! THANKS <3333
castortr0y [4]

Answer:

2 5 7

Step-by-step explanation:

hopefully it helps sorry if it wrong

8 0
2 years ago
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