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2 years ago

What are the intercepts of 7x+2y-14z=56

Mathematics

1 answer:

Rainbow [258]2 years ago

6 0

Hey there!

I believe your answer should be: OPTION B. because

7x + 2y - 14z = 56

7(8) + 2(28) - 14(4) = 56

56 + 56 - 56 = 56

112 - 56 = 56

56 = 56

So, that’s why possibly Option B. could be your result

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

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Step $1$

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we know that

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$ML^{2} =NL^{2} +MN^{2}$

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in this problem

$ML=25\ units\\ NL=15\ units$

Substitute in the formula above

$MN^{2}=25^{2} -15^{2}$

$MN^{2}=400$

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Step $2$

<u>Find the value of cos (M)</u>

we know that

in the right triangle MNL

$cos (M)=\frac{adjacent\ side\ angle\ M}{hypotenuse}$

$adjacent\ side\ angle\ M=MN=20\ units\\ hypotenuse=ML=25\ units$

Substitute

$cos (M)=\frac{20}{25}$

$cos (M)=\frac{4}{5}$

$cos (M)=0.8$

therefore

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