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4 years ago

Do ∠ABE and ∠DBC share a ray?

Mathematics

1 answer:

Thepotemich [5.8K]4 years ago

5 0

Answer:

yes, it's ray

Step-by-step explanation:

because there are two parallel lines

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On August 21, 2009, the World Health Organization announced its prediction that the number of new cases of H1N1 (swine flu) viru

sertanlavr [38]

Answer:

growth rate = 0.1733 per day, or 17.33% per day

Step-by-step explanation:

Since the doubling time is 4 days, the growth factor over a period of t days is ...

2^(t/4)

Then the growth factor for 1 day is

2^(1/4) ≈ 1.189207

The instantaneous growth rate is the natural log of this:

ln(1.189207) ≈ 0.1733 . . . per day

4 0

3 years ago

Flip a coin and toss a 1-6 number cube. Probability of: (heads and not a 3)

jeka94

When finding the probability of two things happening, you multiply the probability of each individual thing happening. The chances of heads are 1/2 and the chances of not a 3 are 5/6. 1/2*5/6 = 5/12. The probability of that is 5/12

3 0

3 years ago

In ΔQRS, q = 960 cm, r = 420 cm and ∠S=31°. Find the area of ΔQRS, to the nearest square centimeter.

Hitman42 [59]

Answer: 103832

Step-by-step explanation:

7 0

3 years ago

QUICK PLSS 1. Jabo orders a meal that cost $20.00.

Lelechka [254]

Answer:

$25.80

Step-by-step explanation:

Find the cost of the meal with the sales tax:

20 x 0.075 = 1.5

Add the sales tax to the total

20 + 1.5 = 21.50

Find the tip:

21.5 x 0.2 = 4.3

Add the tip to the total cost so far:

21.50 + 4.30 = 25.80

7 0

3 years ago

An Airliner has a capacity for 300 passengers. If the company overbook a flight with 320 passengers, What is the probability tha

TEA [102]

Answer:

The probability is $P(X >300 ) = 0.97219$

Step-by-step explanation:

From the question we are told that

The capacity of an Airliner is k = 300 passengers

The sample size n = 320 passengers

The probability the a randomly selected passenger shows up on to the airport

$p = 0.96$

Generally the mean is mathematically represented as

$\mu = n* p$

=> $\mu = 320 * 0.96$

=> $\mu = 307.2$

Generally the standard deviation is

$\sigma = \sqrt{n * p * (1 -p ) }$

=> $\sigma = \sqrt{320 * 0.96 * (1 -0.96 ) }$

=> $\sigma =3.50$

Applying Normal approximation of binomial distribution

Generally the probability that there will not be enough seats to accommodate all passengers is mathematically represented as

$P(X > k ) = P( \frac{ X -\mu }{\sigma } > \frac{k - \mu}{\sigma } )$

Here $\frac{ X -\mu }{\sigma } =Z (The \ standardized \ value \ of \ X )$

=> $P(X >300 ) = P(Z > \frac{300 - 307.2}{3.50} )$

Now applying continuity correction we have

$P(X >300 ) = P(Z > \frac{[300+0.5] - 307.2}{3.50} )$

=> $P(X >300 ) = P(Z > \frac{[300.5] - 307.2}{3.50} )$

=> $P(X >300 ) = P(Z > -1.914 )$

From the z-table

$P(Z > -1.914 ) = 0.97219$

$P(X >300 ) = 0.97219$

8 0

3 years ago