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2 years ago

Savannah runs a day care center. Of the 12 children at the day care center, 3 of them are

Mathematics

1 answer:

sertanlavr [38]2 years ago

6 0

Answer:

$\frac{1}{4}$

Step-by-step explanation:

3 out of 12 children at the day care center are 5-year-olds. So, the probability of a randomly selected child being a five-year old is $\frac{3}{12}$ , or $\frac{1}{4}$ .

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Probability. <br><br> CORRECT answer gets brainliest.

Dima020 [189]

The probability of spinning on yellow would be 1/3 because this is broken into 3 pieces and that would be the probability of something that has been broken into 3 pieces, and 1/3 in decimal form would be 0.33.

The probability of spinning a blue would be 1/2 because the blue is broken into 1/2 of the spinner, therefore the probability of spinning a blue would be 1/2, and 1/2 in decimal form would be 0.5.

Therefore your answers are,

Blue=0.5

Yellow=0.33

3 0

3 years ago

Write in Standard Form:<br><br> 9a^2 + 5 = 0

Levart [38]

<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3

Answer:

It is in standard form!!!

<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3

4 0

2 years ago

of people of the same sex and similar ages follow a Normal distribution reasonably closely. Weights, on the other hand, are not

Margaret [11]

Answer:

Right-skewed

Step-by-step explanation:

The shape of the weight distributed is skewed, because the mean and the median are not equal.

Moreover, the distribution is right-skewed because the mean is greater than the median and because the mean is influenced by the tail of large values.

7 0

3 years ago

Annual returns on stock of the Mean Corporation are approximately normally distributed with a mean of 13.9% and standard deviati

maw [93]

Answer:

(a) z=-0.59

(b) Joe will invest in Mean Corporation. The probability of getting an annual return grater than 11% is 72.3%.

Step-by-step explanation:

We have a normal distribution for the annual return of the stock.

This distribution has mean of 13.9% and s.d. of 4.9%.

If X=11%, we can calculate its corresponding z-value as:

$z=\frac{X-\mu}{\sigma}= \frac{0.11-0.139}{0.049}= -0.5918$

The z-value is z=-0.5918.

The probabilty of P(X>11%)=P(y>-0.5918) is, by the standarized normal distribution table, equal to 0.723.

As its P(y>-0.5918)=P(X>11%)=0.723 bigger than the 70% threshold, Joe will invest in Mean Corporation.

3 0

2 years ago

1. Use the given Taylor polynomial p 2 to approximate the given quantity.

KiRa [710]

Answer:

Part 1:

P₂(0.07)=0.93245≈ $e^{-0.07}$

Part 2:

Error= $0.5618*10^{-4}$

Step-by-step explanation:

Given:

$f(x)=e^{x}\\f(-0.07)=e^{-0.07}$

P₂(x)= $1-x+\frac{x^2}{2}$

Solution:

Part 1:

P₂(x)= $1-x+\frac{x^2}{2}$

We have x=0.07

Put Value of x in above Equation:

P₂(0.07)= $1-0.07+\frac{0.07^2}{2}$

P₂(0.07)=0.93245≈ $e^{-0.07}$

Part 2:

$e^{-0.07}$ =0.93239382 (Calculated using Calculator)

Error=| $e^{-0.07}$ -P₂(0.07)|=|0.93239382-0.93245|=0.00005618

Error=|0.93239382-0.93245|

Error=0.00005618

Error= $0.5618*10^{-4}$

6 0

2 years ago