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liraira [26]
2 years ago
6

Plz guys help me In 2 please

Mathematics
1 answer:
Doss [256]2 years ago
7 0

Answer:

Step-by-step explanation:

OMG!!!!! why don't you just SAY YOU WANT a BLEEPING  REFLECTION!!!

I had to search through a slew of your questions to get clues as to what to do.

To reflect over the x axis, just negate the y term and leave the x term as it is.

M becomes (2, -1)

N becomes (-3, -1)

P becomes (-1, -4)

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2 years ago
(Ross 5.15) If X is a normal random variable with parameters µ " 10 and σ 2 " 36, compute (a) PpX ą 5q (b) Pp4 ă X ă 16q (c) PpX
pochemuha

Answer:

(a) 0.7967

(b) 0.6826

(c) 0.3707

(d) 0.9525

(e) 0.1587

Step-by-step explanation:

The random variable <em>X</em> follows a Normal distribution with mean <em>μ</em> = 10 and  variance <em>σ</em>² = 36.

(a)

Compute the value of P (X > 5) as follows:

P(X>5)=P(\frac{x-\mu}{\sigma}>\frac{5-10}{\sqrt{36}})\\=P(Z>-0.833)\\=P(Z

Thus, the value of P (X > 5) is 0.7967.

(b)

Compute the value of P (4 < X < 16) as follows:

P(4

Thus, the value of P (4 < X < 16) is 0.6826.

(c)

Compute the value of P (X < 8) as follows:

P(X

Thus, the value of P (X < 8) is 0.3707.

(d)

Compute the value of P (X < 20) as follows:

P(X

Thus, the value of P (X < 20) is 0.9525.

(e)

Compute the value of P (X > 16) as follows:

P(X>16)=P(\frac{x-\mu}{\sigma}>\frac{16-10}{\sqrt{36}})\\=P(Z>1)\\=1-P(Z

Thus, the value of P (X > 16) is 0.1587.

**Use a <em>z</em>-table for the probabilities.

8 0
3 years ago
Complete the angle addition postulate for the following angle
aev [14]

Answer: AOB

This is because angle AOB on top adds with BOC down below to get the largest angle AOC. See the diagram below.

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2 years ago
Find the sum of 0.482 and 482.3152
Airida [17]

Answer:482.7972

Step-by-step explanation:

7 0
3 years ago
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