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harkovskaia [24]
4 years ago
9

Solve P=a+2b+3c for b

Mathematics
2 answers:
Molodets [167]4 years ago
7 0
What you do here is, isolate everything to solve for the variable b. Steps as following:

P-3c=a+2b
P-3c-a=2b
(P-3c-a)/2=b


Final answer: (P-3c-a)/2 = b
Gwar [14]4 years ago
3 0
If you're solving for b, that means you want to isolate b to one side.

P = a + 2b + 3c

Subtract 3c from both sides:

P - 3c = a + 2b

Subtract a from both sides:

P - 3c - a = 2b

Divide both sides by 2:

b = (P - 3c - a)/2
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Macs hotel has 128 rooms, and 25% of the rooms in the hotel did not have an ocean view. Write an expression to find the total nu
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the expression u could use is

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4 years ago
A high school is hosting a blood drive. The sign-up sheet has 5 slots available for Mr. Bentley’s class and 6 slots available fo
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3 years ago
Answer the questions attached about the given sequence: -33, -27, -21, -15, ...
Arte-miy333 [17]

Answer:

see below

Step-by-step explanation:

-33, -27, -21, -15,....

-33 +6 = -27  

-27+6 = -21

-21+6 = -15

This is an arithmetic sequence

The common difference is +6

explicit formula

an=a1+(n-1)d  where n is the term number and d is the common difference

an = -33 + ( n-1) 6

an = -33 +6n -6

an = -39+6n

recursive formula

an+1 = an +6

10th term

n =10

a10  = -39+6*10

      = -39+60

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sum formula

see image

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7 0
4 years ago
A data set lists earthquake depths. The summary statistics are
irinina [24]

Answer:

Step-by-step explanation:

The summary of the given statistics data include:

sample size n = 400

sample mean \overline x = 6.86

standard deviation = 4.37

Level of significance ∝ = 0.01

Population Mean \mu = 6.00

Assume that a simple random sample has been selected. Identify the null and alternative​ hypotheses, test​ statistic, P-value, and state the final conclusion that addresses the original claim.

To start with the hypothesis;

The null and the alternative hypothesis can be computed as :

H_o: \mu = 6.00 \\ \\  H_1 : \mu \neq 6.00

The test statistics for this two tailed test can be computed as:

z= \dfrac{\overline x - \mu}{\dfrac{\sigma}{\sqrt {n}}}

z= \dfrac{6.86 - 6.00}{\dfrac{4.37}{\sqrt {400}}}

z= \dfrac{0.86}{\dfrac{4.37}{20}}

z = 3.936

degree of freedom = n - 1

degree of freedom = 400 - 1

degree of freedom = 399

At the level of significance ∝ = 0.01

P -value = 2 × (z < 3.936)  since it is a two tailed test

P -value = 2 × ( 1  - P(z ≤ 3.936)

P -value = 2 × ( 1  -0.9999)

P -value = 2 × ( 0.0001)

P -value =  0.0002

Since the P-value is less than level of significance , we reject H_o at level of significance 0.01

Conclusion: There is sufficient evidence to conclude that the original claim that the mean of the population of earthquake depths is  5.00 km.

7 0
3 years ago
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