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3 years ago

1. A chord is 22 cm long. It is 60 cm from the center of the circle.

Mathematics

1 answer:

mezya [45]3 years ago

3 0

Answer:

Radius, r = 61 cm

Step-by-step explanation:

According to the attached figure, we have,

Length of chord, AB = 22 cm

Such that, AP = PB = 11 cm

OP = 60 cm

It is required to find the radius of the circle. We know that radius of a circle is perpendicular to chord. So, APO forms a right angled triangle. Using Pythagoras theorem to find the radius of circle. Let it is r. So,

$r^2=60^2+11^2\\\\r=61\ cm$

So, the radius of the circle is 61 cm.

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kozerog [31]

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3 years ago

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MAXImum [283]

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3 years ago

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3 years ago

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eimsori [14]

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4 0

3 years ago

HELP PLEASE WILL MARK BRAINLIEST!!

Arte-miy333 [17]

Answer:

Answer is option d)346.4 ft

Step-by-step explanation:

$from \: the \: figure \\ AB = 300 \: ft \: \: \: angle \: C = 60 \:( theta)\: degress \\ in \: triangle \: ABC \: using \: tan \: theta\\ \tan(60) = \frac{opposite \: side}{adjacent \: side} \\ \tan(60) = \frac{300}{BC} \\ \sqrt{3} = \frac{300}{BC} \\ BC = \frac{300}{ \sqrt{3} } \\ BC = 100 \sqrt{3} ft \\ then \: in \: triangle \: ABD \: using \: tan \: theta \\ angle \: D = 30 \: degrees \: (theta) \\ \tan(30 ) =\frac{opposite \: side}{adjacent \: side} \\ \tan(30) = \frac{300}{BD} \\ \frac{1}{ \sqrt{ 3} } = \frac{300}{BD} \\ BD = 300 \sqrt{3} \\ CD = BD - BC \\ = 300 \sqrt{3 } - 100 \sqrt{3} \\ = (300 - 100) \sqrt{3} \\ = 200 \sqrt{3 } \\ = 200 \times 1.732 \\ = 346.4 \: ft$

HAVE A NICE DAY!

THANKS FOR GIVING ME THE OPPORTUNITY TO ANSWER YOUR QUESTION. 

7 0

3 years ago