All categories

3 years ago

1. A chord is 22 cm long. It is 60 cm from the center of the circle.

Mathematics

1 answer:

mezya [45]3 years ago

3 0

Answer:

Radius, r = 61 cm

Step-by-step explanation:

According to the attached figure, we have,

Length of chord, AB = 22 cm

Such that, AP = PB = 11 cm

OP = 60 cm

It is required to find the radius of the circle. We know that radius of a circle is perpendicular to chord. So, APO forms a right angled triangle. Using Pythagoras theorem to find the radius of circle. Let it is r. So,

$r^2=60^2+11^2\\\\r=61\ cm$

So, the radius of the circle is 61 cm.

You might be interested in

Anyone help plzzzzzzz?

Blizzard [7]

The answer is D. The ones on the left are the domain. The ones on the right which the arrows point to are the range

7 0

3 years ago

Which table represents a nonlinear function?

Y_Kistochka [10]

Answer:C

Step-by-step explanation: When a table represents a nonlinear function, the rate of change is not constant. A wouldn't be the answer because the rate of change is always +10 (you would add 10 to get from -9 to 1; you would add 10 to get from 1 to 10) . It wouldn't be B because the rate of change is always -2, and the rate of change for D is always +3. For C, however, the rate of change is not constant all the way through (to get from 0 to 6, you would add 6, but to get from 6 to 16 you add 10).

5 0

3 years ago

Perform the operation and write the answer in simplest form.<br><br> 637÷11314

Step2247 [10]

Answer:

0.0563

the fraction cannot be simplified

7 0

3 years ago

7. Jenny is saving to buy a laptop worth $960. Her parents promise to match every $3 saved

PSYCHO15rus [73]

First off, if you divide $960/$8, you will get 120 “sets” of payment. Multiply this value by the amount of money Jenny is responsible for paying and the amount her parents are responsible for paying to find their total contributions.

a. Jenny will have to pay $600

b. Jenny’s parents will contribute $360 to her new laptop.

8 0

3 years ago

How would I find the integral of <img src="https://tex.z-dn.net/?f=%5Cint%5Cfrac%7Btdt%7D%7Bt%5E4%2B2%7D" id="TexFormula1" title

kotegsom [21]

Let $t=\sqrt y$ , so that $t^2=y$ , $t^4=y^2$ , and $\mathrm dt=\dfrac{\mathrm dy}{2\sqrt y}$ . Then

$\displaystyle\int\frac t{t^4+2}\,\mathrm dt=\int\frac{\sqrt y}{2\sqrt y(y^2+2)}\,\mathrm dy=\frac12\int\frac{\mathrm dy}{y^2+2}$

Now let $y=\sqrt2\tan z$ , so that $\mathrm dy=\sqrt2\sec^2z\,\mathrm dz$ . Then

$\displaystyle\frac12\int\frac{\mathrm dy}{y^2+2}=\frac12\int\frac{\sqrt2\sec^2z}{(\sqrt2\tan z)+2}\,\mathrm dz=\frac{\sqrt2}4\int\frac{\sec^2z}{\tan^2z+1}\,\mathrm dz=\frac1{2\sqrt2}\int\mathrm dz=\dfrac1{2\sqrt2}z+C$

Transform back to $y$ to get

$\dfrac1{2\sqrt2}\arctan\left(\dfrac y{\sqrt2}\right)+C$

and again to get back a result in terms of $t$ .

$\dfrac1{2\sqrt2}\arctan\left(\dfrac{t^2}{\sqrt2}\right)+C$

3 0

3 years ago